Solved

<img> tag within <button> tag

Posted on 2010-08-16
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Last Modified: 2012-05-10
i want to raise onclick event of <img> tag which is inside the <button> tag
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Question by:infoplus
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23 Comments
 
LVL 19

Expert Comment

by:Amandeep Singh Bhullar
ID: 33451669
can you post the code.
0
 
LVL 10

Expert Comment

by:Jini Jose
ID: 33451674
why you need a img tag inside a button? there is another imagebutton control in asp.net.
0
 

Author Comment

by:infoplus
ID: 33451676
<button type="button" name="btnUp" id="id_btnUp" onclick="btnClick()">Click Me<img alt="submit" src="images/images.jpg" hspace="0" border="0" align="top" onclick="btnImg()"> /></button>

i have to do something on button click and do something for img click.
what should i do, sir?
0
 
LVL 10

Expert Comment

by:Jini Jose
ID: 33451685
so you are calling  javascript functions on the click events or server events ?
0
 

Author Comment

by:infoplus
ID: 33451686
No sir i am creating a control. so i am using html tag. i could not use asp tag
0
 

Author Comment

by:infoplus
ID: 33451688
i have to call separate click events
0
 
LVL 10

Expert Comment

by:Jini Jose
ID: 33451702
can you please tell what for you doing this ?
0
 

Author Comment

by:infoplus
ID: 33451714
i am creating an usercontrol. when i click on the button text, i wil come one javascript function. and when i click image on the button, i will call another javascript function. Now i couldnt raise separate click event. When i click on image "btnClick" only calls..
0
 
LVL 19

Expert Comment

by:Amandeep Singh Bhullar
ID: 33451716
In case of nested controls, you cannot fire the event of the child.
In your case Image click event will never be fired
0
 
LVL 10

Expert Comment

by:Jini Jose
ID: 33451724
why couldnt u use two controls seperately ?
0
 

Author Comment

by:infoplus
ID: 33451725
Ok sir. then what should i do for this situation? can you help me?
0
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Author Comment

by:infoplus
ID: 33451732
I have to display the image within the button control. What to do for this?
0
 
LVL 10

Accepted Solution

by:
Jini Jose earned 100 total points
ID: 33451740
you can use two image for doing two click events
<html>

<head>

    <title>Untitled Page</title>



    <script type="text/javascript">

    function btnClick()

    {

        alert('Btn clicked');

    }

    function btnImg()

    {

        alert('Img clicked');

    }

    </script>



</head>

<body>

    <img alt="submit" src="1.gif" width="50" height="50" hspace="0" border="0"

        align="top" onclick="btnImg();">

        <img alt="submit" src="2.gif" width="50" height="50" hspace="0" border="0"

        align="top" onclick="btnClick();">

</body>

</html>

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0
 

Author Comment

by:infoplus
ID: 33451763
i need a single control to do these two tasks.. but u have given 2 separate images
0
 
LVL 27

Expert Comment

by:nmarun
ID: 33451766
AFAIK, the current model of Javascript doe snot allow for this. You're better off separating the two controls and then calling different Javascript functions on each control.

Arun
0
 
LVL 19

Assisted Solution

by:Amandeep Singh Bhullar
Amandeep Singh Bhullar earned 100 total points
ID: 33451768
In case case i can suggest you to use the image map.
This is the only way you can do your task

Check the link for the same
http://www.javascriptkit.com/howto/imagemap.shtml

Hope this will help you
0
 

Author Comment

by:infoplus
ID: 33451836
No sir.. not like that... anyway thanks for your try
0
 
LVL 14

Assisted Solution

by:Dhanasekaran Sengodan
Dhanasekaran Sengodan earned 100 total points
ID: 33452185
Solution 1 :
==========

<html>
<head>
    <title>Untitled Page</title>

    <script type="text/javascript">
    function btnClick()
    {
        alert('Btn clicked');
        btnImg();
    }
    function btnImg()
    {
        alert('Img clicked');
    }
    </script>
<style>
.buttons
{
background:url(/images/Btn.PNG) no-repeat;
cursor:pointer;
width: 200px;
height: 100px;
border: none;
}
</style>
</head>
<body>
  <button type="button" name="btnUp" id="id_btnUp" onclick="javascript:btnClick()" class="buttons">Click Me </button>
</body>
</html>


Solution : 2
=========

http://sophie-g.net/jobs/css/e_buttons.htm



0
 
LVL 14

Assisted Solution

by:raja_ind82
raja_ind82 earned 100 total points
ID: 33453099
HI,
Small work around for your situation. Please try this.

Regards,
Raja Muthaiah
<html>

<head>

    <title>Untitled Page</title>



    <script type="text/javascript">

    function btnClick()

    {

	if(hdnMode.value=="M")

	        alert('Image clicked');

	else

	        alert('Btn clicked');



    }

    function btnImg()

    {

        alert('Img clicked');

    }

    function btnMouse()

    {

	hdnMode.value="M";

    }

function btnMouseOut()

    {



	hdnMode.value="";

    }



    </script>



</head>

<body>

<input type="hidden" name="hdnMode" value="">

<button type="button" name="btnUp" id="id_btnUp" onclick="btnClick()">Click Me

<img alt="submit" src="images/images.jpg" hspace="0" border="0" align="top" onclick="btnImg()"

 onmouseover="btnMouse();" onmouseout="btnMouseOut();"/>

</button>



</body>

</html>

Open in new window

0
 
LVL 4

Expert Comment

by:ultrawebsites
ID: 33459929
Hi there
Perhaps you can post an image of what you want the button and image to look like?
And perhaps explain what you want to achieve, as maybe there is a better way to achieve it too?
Cheers
Matt
0
 
LVL 14

Expert Comment

by:raja_ind82
ID: 33461511
HI,
Have you check my solution. Its exactly fulfill your requirement.
Please let me know if you have any quries...

regards,
Raja Muthaiah
0
 
LVL 27

Assisted Solution

by:nmarun
nmarun earned 100 total points
ID: 33461886
Raja, your solution does not work. You cannot access controls in javascript by just their name. You need do find them by their id using document.getElementById().

The below worked for me and also note that you don't need a click event on your image.

Arun

<input type="hidden" name="hdnMode" value="" id="hdnMode" />

<button type="button" name="btnUp" id="Button1" onclick="btnClick()">

    Click Me

    <img alt="submit" src="images/home.png" hspace="0" border="0" align="top"

        onmouseover="btnMouse();" onmouseout="btnMouseOut();" />

</button>



<script type="text/javascript">

function btnClick() {

    if (document.getElementById("hdnMode").value == "M")

        alert('Image clicked');

    else

        alert('Btn clicked');



}



function btnMouse() {

    document.getElementById("hdnMode").value = "M";

}

function btnMouseOut() {



    document.getElementById("hdnMode").value = "";

}

</script>

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