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Get 1st row of data into a variable

Posted on 2010-08-17
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Last Modified: 2013-11-18
I have an xml file as seen below: what I need to get is the values in the first row to set some values in before I process all the rows in the row template.  

I can not figure out how to getl the data in the first row by itself before I run the row template.

XML -data
<?xml version="1.0"?>
<document>
  <row>
    <column1>20100810</column1>
    <column2>20100815</column2>
    <column3>20100817</column3>
    <column4>WLP_PCN_SL_regular_20100816.out</column4>
  </row>
  <row>
    <column1>01300</column1>
  </row>
  <row>
    <column1>01820</column1>
  </row>
  <row>
    <column1>02282</column1>
  </row>
</document>

XSL
  <xsl:template match="/">
    <xsl:apply-templates select="document"/>
  </xsl:template>

  <xsl:template match="document">
  <xsl:variable name="vNameOfDataFile" select="row/@column1"/>

          <ProcessStartWorkDate>
            <Date><xsl:value-of select="$vNameOfDataFile"/></Date>
          </ProcessStartWorkDate>
           
      <xsl:for-each select="row">
        <xsl:apply-templates select="."/>
      </xsl:for-each>
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Question by:johnth1957
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8 Comments
 
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Expert Comment

by:Geert Bormans
ID: 33455455
<xsl:variable name="vNameOfDataFile" select="row[1]/@column4"/>
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Expert Comment

by:Geert Bormans
ID: 33455644
the [1] tells you that you need the first row
the name of data file seems to be in column four
note that this variable can only be used in this template,
if you want a global variable put this at the highest level

<xsl:variable name="vNameOfDataFile" select="/document/row[1]/@column4"/>
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Author Comment

by:johnth1957
ID: 33455773
Thanks, I just tried that and still not getting a value in that variable .
0
 

Author Comment

by:johnth1957
ID: 33455824
Yes that is the correct column for the variable but I was just trying to get something to work in case I was pulling off another record.
I am declaring and using the variable in the same template.
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Accepted Solution

by:
Geert Bormans earned 500 total points
ID: 33455827
of course, the @ should not be there, error in copy and pasting from your mistake, sorry
    <xsl:variable name="vNameOfDataFile" select="/document/row[1]/column4"/>
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Expert Comment

by:Geert Bormans
ID: 33455841
or
<xsl:template match="document">
    <xsl:variable name="vNameOfDataFile" select="row[1]/column4"/>
    <xsl:value-of select="$vNameOfDataFile"/>
</xsl:template>
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Author Closing Comment

by:johnth1957
ID: 33455904
Thanks!
0
 
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Expert Comment

by:Geert Bormans
ID: 33455914
welcome
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