Regular expression in vba for excel

I looking stumped on how to write the regexp for this word pattern "Node XXX 200Z"  where "x" could be 1-999  and "z" could be any number 1-9
rpelfreyAsked:
Who is Participating?
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

javaftperCommented:
I have written a sub to call a function which returns 'No match' if the pattern fails or the node name if a match is found-

Sub TestText()
    Const strTest As String = "Node 769 2009" 'test value
    MsgBox REGEXTEST(strTest)
End Sub

Function REGEXTEST(strData As String) As String
    Dim RE As Object, REMatches As Object

    Set RE = CreateObject("vbscript.regexp")
    With RE
        .MultiLine = False
        .Global = False
        '.IgnoreCase = True if necessary you can ignore case
        .Pattern = "(Node )[1-9][1-9][1-9]( )(200[1-9])"
    End With
   
    Set REMatches = RE.Execute(strData)
    If REMatches.Count = 0 Then
    REGEXTEST = "No match"
    Else
    REGEXTEST = REMatches(0)
    End If
   

End Function
0
byundtCommented:
Assuming that the pattern ought to allow for "Node 900 2008", I modified javaftper's code with the following statement:
 .Pattern = "Node\s([1-9]\d{2})\s200([1-9])"
0
byundtCommented:
My pattern put the xxx and y parts of the pattern within parentheses so you can retrieve the submatches separately. With reference to javaftper's Else statement:
    REGEXTEST = REMatches(0).submatches(0) & " " & REMatches(0).submatches(1)   'Retrieve xxx and y separately
0
Cloud Class® Course: SQL Server Core 2016

This course will introduce you to SQL Server Core 2016, as well as teach you about SSMS, data tools, installation, server configuration, using Management Studio, and writing and executing queries.

rpelfreyAuthor Commented:
I am getting "No Match" see attached

samplenode.xls
0
byundtCommented:
Change the pattern as follows:
.Pattern = "Node\s+([1-9]\d{0,2})\s+200([1-9])"

All nodes will match, even those with more than one space. If you require exactly one space, then remove the two + from the pattern.
0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
rpelfreyAuthor Commented:
That did it.  I was using a vb script  that I had found that allows you to define the pattern while implementing the search/function (=RegExpFind(B1,"Node\s+([1-9]\d{0,2})\s+200(9)").  

It was written by matthewspatrick at this site http://www.vbaexpress.com.  I just could not defined the pattern properly.
0
rpelfreyAuthor Commented:
Great Job!!!!
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft Excel

From novice to tech pro — start learning today.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.