Solved

SQL Join to join 2 select statments

Posted on 2010-08-17
13
485 Views
Last Modified: 2012-05-10
Hello all,
sorry for my query, it's a long one

basically it consists of 2 select statements on 2 tables, each select statement gets the top 10 and self join it to the rest 90 as others.

now I need to join the 2 statements together full join, as there's of course different top 10s in each of them.

here's my query but it gives me weird results !! only results from the second statement and 3 NULL columns !!

please tell me if sample data is needed.

SELECT a.[Service Code]
, a.[Department Total]
, a.[Percentage]
from
(SELECT [Service Code]
, [Department Total]
, [Percentage]
from(
SELECT TOP 10
[Service Code]
,Sum([Total Charges]) AS [Department Total]
,Sum([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-COMM] Where [Fac Name] like '%Michaels%') AS [Percentage]
from dbo.[XACTIMED-COMM]
Where [Fac Name] like '%Michaels%'
GROUP BY
[Service Code]
ORDER BY
[Department Total] DESC
) AS Q1
UNION ALL
SELECT
'Other' AS [Service Code]
,Sum([Total Charges]) AS [Department Total]
,Sum([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-COMM]) AS [Percentage]
from dbo.[XACTIMED-COMM]
Where [Fac Name] like '%Michaels%'
and
[Service Code] NOT IN (SELECT TOP 10
[Service Code]
from dbo.[XACTIMED-COMM]
Where [Fac Name] like '%Michaels%'
GROUP BY
[Service Code]
ORDER BY
Sum([Total Charges]) DESC))a


full join



(SELECT [Service Code]
, [Department Total]
, [Percentage]
from(
SELECT TOP 10
[Service Code]
,Sum([Total Charges]) AS [Department Total]
,Sum([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-CARE] Where [Fac Name] like '%Michaels%') AS [Percentage]
from dbo.[XACTIMED-CARE]
Where [Fac Name] like '%Michaels%'
GROUP BY
[Service Code]
ORDER BY
[Department Total] DESC
) AS Q2
UNION ALL
SELECT
'Other' AS [Service Code]
,Sum([Total Charges]) AS [Department Total]
,Sum([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-CARE]) AS [Percentage]
from dbo.[XACTIMED-CARE]
Where [Fac Name] like '%Michaels%'
and
[Service Code] NOT IN (SELECT TOP 10
[Service Code]
from dbo.[XACTIMED-CARE]
Where [Fac Name] like '%Michaels%'
GROUP BY
[Service Code]
ORDER BY
Sum([Total Charges]) DESC))d

on d.[Service Code] = a.[Service Code]

Open in new window


can somebody help me please.

Thanks results
0
Comment
Question by:Jason Yousef, MS
  • 6
  • 5
  • 2
13 Comments
 
LVL 16

Expert Comment

by:vdr1620
ID: 33457166
can you provide sample data from the tables along with table structure ??
0
 
LVL 21

Author Comment

by:Jason Yousef, MS
ID: 33457283
Hi vdr1620:

thanks for your reply.
here you go attached.

sample-data-x.txt
0
 
LVL 2

Expert Comment

by:ajisasaggi
ID: 33457285
Could you please state your requirement? Do the individual statements produce expected results?

If it is combining the results of the 2 separate queries, then you should do a UNION of the statements instead of JOIN.
0
 
LVL 21

Author Comment

by:Jason Yousef, MS
ID: 33457309
ajisasaggi:  thanks for stepping in, union gives me duplicates, doesn't sum all the same service departments.

can't figure it out !
0
 
LVL 2

Expert Comment

by:ajisasaggi
ID: 33457463
So do you want to sum the totals, [Service Code] wise, from both statements?
What about 'Other'? Do you want a single row with combined totals?
0
 
LVL 16

Expert Comment

by:vdr1620
ID: 33457511
Thanks for data..but go to go.. will work on it as soon as i come back
0
Control application downtime with dependency maps

Visualize the interdependencies between application components better with Applications Manager's automated application discovery and dependency mapping feature. Resolve performance issues faster by quickly isolating problematic components.

 
LVL 21

Author Comment

by:Jason Yousef, MS
ID: 33457542
ajisasaggi:  yes, need to sum all the departments that match and other too.

as it's a combined 2 statements together
0
 
LVL 2

Expert Comment

by:ajisasaggi
ID: 33457801
Please try the attached query.
It can be cleaned up quite a bit (percentage values from inner queries can be removed).

query.sql
0
 
LVL 21

Author Comment

by:Jason Yousef, MS
ID: 33458076
ajisasaggi:  thank you, but it gave me error, attached.

I'm using sql server 2008 dev

error.gif
0
 
LVL 2

Expert Comment

by:ajisasaggi
ID: 33458457
Please try the attached query.
The idea is to combine the results of the 4 inner SELECT statements and apply grouping on the resultset.
query.sql
0
 
LVL 21

Author Comment

by:Jason Yousef, MS
ID: 33458548
ajisasaggi: thanks for your help, but what version of sql you're using? how come it works for you and i keep getting errors !

I got punch of Incorrect syntax near ')'
0
 
LVL 2

Accepted Solution

by:
ajisasaggi earned 500 total points
ID: 33458862
My bad, I didn't validate the syntax.

Please try with this. I have modified the query to return the top 10 departments that have a combined higher total and an additional row with the accumulated total for all other departments.
SELECT [Service Code], [Department Total]
FROM
(
    SELECT TOP 10 [Service Code], SUM([Total Charges]) AS [Department Total]
        , SUM([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-COMM] Where [Fac Name] like '%Michaels%') + (Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-CARE] Where [Fac Name] like '%Michaels%') AS [Percentage]
    FROM
    (
        SELECT [Service Code], [Total Charges]
        from dbo.[XACTIMED-COMM]
        Where [Fac Name] like '%Michaels%'
        union all
        SELECT [Service Code], [Total Charges]
        from dbo.[XACTIMED-CARE]
        Where [Fac Name] like '%Michaels%'
    ) AS ALL_DEPT
    GROUP BY [Service Code]
    ORDER BY [Department Total] DESC
) AS TOP_TEN

UNION ALL

SELECT 'Other' [Service Code], SUM([Total Charges]) AS [Department Total]
    , SUM([Total Charges])/(Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-COMM] Where [Fac Name] like '%Michaels%') + (Select SUM([Total Charges]) from [ExctemedDB].[dbo].[XACTIMED-CARE] Where [Fac Name] like '%Michaels%') AS [Percentage]
FROM
(
    SELECT [Service Code], [Total Charges]
    from dbo.[XACTIMED-COMM]
    Where [Fac Name] like '%Michaels%'
    union all
    SELECT [Service Code], [Total Charges]
    from dbo.[XACTIMED-CARE]
    Where [Fac Name] like '%Michaels%'
) AS ALL_DEPT
WHERE [Service Code] NOT IN (
    SELECT TOP 10 [Service Code]
    FROM
    (
        SELECT [Service Code], [Total Charges]
        from dbo.[XACTIMED-COMM]
        Where [Fac Name] like '%Michaels%'
        union all
        SELECT [Service Code], [Total Charges]
        from dbo.[XACTIMED-CARE]
        Where [Fac Name] like '%Michaels%'
    ) AS ALL_DEPT
    GROUP BY [Service Code]
    ORDER BY [Department Total] DESC
)

Open in new window

0
 
LVL 21

Author Closing Comment

by:Jason Yousef, MS
ID: 33559261
Thanks for trying, but still a lot of syntax errors, I did it in a different way though.
0

Featured Post

Enterprise Mobility and BYOD For Dummies

Like “For Dummies” books, you can read this in whatever order you choose and learn about mobility and BYOD; and how to put a competitive mobile infrastructure in place. Developed for SMBs and large enterprises alike, you will find helpful use cases, planning, and implementation.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Audit has been really one of the more interesting, most useful, yet difficult to maintain topics in the history of SQL Server. In earlier versions of SQL people had very few options for auditing in SQL Server. It typically meant using SQL Trace …
After restoring a Microsoft SQL Server database (.bak) from backup or attaching .mdf file, you may run into "Error '15023' User or role already exists in the current database" when you use the "User Mapping" SQL Management Studio functionality to al…
Need to grow your business through quality cloud solutions? With everything required to build a cloud platform and solution, you may feel like the distance between you and the cloud is quite long. Help is here. Spend some time learning about the Con…
With Secure Portal Encryption, the recipient is sent a link to their email address directing them to the email laundry delivery page. From there, the recipient will be required to enter a user name and password to enter the page. Once the recipient …

919 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

21 Experts available now in Live!

Get 1:1 Help Now