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Batch File: Short Name of Long File Name

Posted on 2010-08-18
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Last Modified: 2012-05-10
Hi there,

I need to copy files as their short file name.

@echo off
for /f "delims=" %%A in (dir /b /s .\Documents') do xcopy /y %%?A Z:\Documents
exit

Thanks for your help,
Rene
0
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Question by:ReneGe
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7 Comments
 
LVL 56

Expert Comment

by:Bill Prew
ID: 33464275
In a FOR loop you can get the short names via the "S" modifier, so perhaps:

for /f "delims=" %%A in (dir /b /s .\Documents') do xcopy /y %%~sA Z:\Documents

You can do FOR /? at a command prompt to see all the modifiers...

~bp
0
 
LVL 10

Author Comment

by:ReneGe
ID: 33464303
Hey billprew !!

I clicked on the send button to quickly. So while I was editing my question you answered... Yr quicker than a speeding bullet...

It must be done by excluding the drive infos.
So insted of: C:\Documents\mydocu~1
I would get: \mydocu~1

Thanks,
Rene
0
 
LVL 10

Author Comment

by:ReneGe
ID: 33464366
Correction:
It must be done by excluding the drive infos.
So insted of: C:\Docume~1\mydocu~1
I would get: \mydocu~1   or   mydocu~1
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LVL 56

Accepted Solution

by:
Bill Prew earned 500 total points
ID: 33467773
I'm not quite sure I understand what you want, but how about these?

for /f "delims=" %%A in ('dir /b /s .\Documents') do xcopy /y %%~spnxA Z:\Documents

or

for /f "delims=" %%A in ('dir /b /s .\Documents') do xcopy /y %%~snxA Z:\Documents

Also, you don't even need the DIR command in this case, and can get faster results via:

for /R ".\Documents" %%A in (.) do xcopy /y %%~spnxA Z:\Documents

~bp
0
 
LVL 10

Author Comment

by:ReneGe
ID: 33471452
billprew,

You answered two questions at once, the one I just asked and the one I was just about to ask... cool!!!

Thanks man...

Cheers,
Rene

0
 
LVL 10

Author Closing Comment

by:ReneGe
ID: 33471462
billprew is the coolest!
0
 
LVL 56

Expert Comment

by:Bill Prew
ID: 33471474
Thanks Rene, glad that was useful.

~bp
0

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