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BrookK

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DATEDIFF function

Hello All,

How do I write T-SQL to calculate if a machine was used with in 24 hours from the last used date and getdate()?

SELECT DATEDIFF(hh, max(LastUsedDate), GETDATE()) FROM Table1. This gives me only in hours but it does not calculate minutes and seconds.

How would I make sure the mm and ss are also taken into consideration?

Thanks,
-B
Avatar of Guy Hengel [angelIII / a3]
Guy Hengel [angelIII / a3]
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>This gives me only in hours but it does not calculate minutes and seconds.
that is by specifications, only the difference in hours.

so: 12:01 and 11:59 are "1 hour" apart, while 12:01 and 12:03 are 0 hours apart...
see the doc: http://msdn.microsoft.com/en-us/library/ms189794.aspx
>Returns the count (signed integer) of the specified datepart boundaries crossed between the specified startdate and enddate.<

so:
>How would I make sure the mm and ss are also taken into consideration?
it depends on what return values you need exactly, based on sample data.
please clarify
I've not tested this but something like this may do what you want?

SELECT * FROM table WHERE DATEADD(hh,24,LastUsedDate) < {fn now()}
SELECT DATEDIFF(hh, max(LastUsedDate) AS HOURS,DATEDIFF(mm, max(LastUsedDate) AS MINUTES,DATEDIFF(ss, max(LastUsedDate) AS SECONDS, GETDATE()) FROM Table1

I hope this is what you are looking for...
The user has used the machine in the last 24 hours

SELECT User, Max(LastUsedDate) as MaxLastUsedDate
FROM Table1
group by User
Having DATEADD(hh, 24, Max(LastUsedDate)) > getdate()
if you want a list of machines that were used in the past 24 hours then it should be in the where clause


select tb.*
from (
  select max(lastused) as lastused, machinename
  from table1
  group by machinename
) as tb
where tb.lastused > datediff(hh, -24, getdate())

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Avatar of BrookK
BrookK

ASKER

For example:

select DATEDIFF(hh, '2010-08-18 08:06:00.000',  '2010-08-19 08:04:00.000') AS DaysDiff
It gives me 24 hours even though there are 2 minutes less for 24 hours between these two date ranges.

It is fine if it gives 23 hours but the accurate answer is 23 hours and 58 minutes.

Thanks,
then what you are probably looking for is to get the datediff by seconds then to display the answer differently:
select machinename, secondsago/3600 as hoursago, (secondsago%3600)/60 as minutesago, (secondsago%3600)%60 as secondsago
from
(
select machinename, datediff(ss, lastused, getdate()) as secondsago
from table1
) t1

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if all times are < 24 hours:
select convert(char(8), cast( '2010-08-19 08:04:00.000' as datetime ) - cast('2010-08-18 08:06:00.000' as datetime), 8) AS DaysDiff
if there are >= 24 hours, you want the day portion:
declare @s varchar(30)
declare @e varchar(30)
set @s = '2010-08-18 08:04:00.000'
set @e = '2010-08-19 08:02:00.000'
select case when cast(  @e as datetime ) - cast( @s as datetime) < 1 then ''
  else cast( cast( cast( @e as datetime ) - cast(@s as datetime) as int) as varchar(10)) + ' ' end
+ convert(char(8), cast( @e as datetime ) - cast(@s as datetime), 8)
AS DaysDiff

set @s = '2010-08-18 08:04:00.000'
set @e = '2010-09-19 08:02:00.000'
select case when cast(  @e as datetime ) - cast( @s as datetime) < 1 then ''
  else cast( cast( cast( @e as datetime ) - cast(@s as datetime) as int) as varchar(10)) + ' ' end
+ convert(char(8), cast( @e as datetime ) - cast(@s as datetime), 8)
AS DaysDiff


output:
23:58:00
32 23:58:00

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Avatar of BrookK

ASKER

I do not want this specific LCS. I just have to add a check for one machine that can I multiple clean events. I have to get the max clean event and see if that is less than or more than current date? If less then error.

Thanks,
--create table table1 (mashine varchar(10), LastUsedDate datetime)

select mashine, convert(varchar(10), getdate() - max(LastUsedDate), 8) as datedifftime
from table1
group by mashine
having (getdate() - max(LastUsedDate)) <= cast('23:59.999' as datetime)
ASKER CERTIFIED SOLUTION
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cyberkiwi
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ASKER

Soln worked!