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Windows Batch - Find Day of Week

Posted on 2010-08-19
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Last Modified: 2012-05-10
Hi,

I have the below batch script to create the 'DOW' variable.  However when I run it, it's choking on the 4th lineon the 'Command' part.  Not sure what is wrong.  Any help?  Prefer to keep this Windows Batch.  Running on Win Server 2003 R2.


REM Set the Day of Week (DOW) Variable
:: setDOW.bat
@echo off
Echo.|Command /C Date>DOW
set /p today=<DOW
set DOW=%today:~16,3%
echo DOW=%DOW%
:: DONE
0
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Question by:elwayisgod
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7 Comments
 

Author Comment

by:elwayisgod
ID: 33477403
result is:

DOW=~16,3

result should be: Thursday
0
 
LVL 53

Expert Comment

by:Bill Prew
ID: 33477477
If you do the following command at a DOS prompt, what does it display?

ECHO %DATE%

~bp
0
 

Author Comment

by:elwayisgod
ID: 33477495
'Command' is not recognized as an internal or external command,
operable program or batch file.
0
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Author Comment

by:elwayisgod
ID: 33477503
X:\Sam_LREF\EssbaseBackup\maxl>echo %Date%
Thu 08/19/2010
0
 

Author Comment

by:elwayisgod
ID: 33477536
I just want the 'Thu' not the rest of it. So my results would always be:

Mon
Tue
Wed
Thu
Fri
Sat
Sun
0
 
LVL 53

Accepted Solution

by:
Bill Prew earned 125 total points
ID: 33477569
In a BAT file, this is all you should need:

@echo off
for /F "tokens=1" %%A in ("%DATE%") do set DOW=%%A

~bp
0
 
LVL 2

Expert Comment

by:PeterGillett
ID: 33477666
If your echo %date% gives Thu 08/19/2010

then you should be able to use:

SET DOW=%date:~0,3%
0

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