Solved

Can not convert a mssql query to a mysql query

Posted on 2010-08-20
5
325 Views
Last Modified: 2012-05-10
Hi I am converting a asp website on a windows server to php on a linux and am having trouble converting one of the mssqls to mysql.

Here is the query as a mssql:

SELECT DISTINCT(v2_dealers.ID), name, town, County, CAST(SQRT(SQUARE(" & x & " - ISNULL(tbl_Postcodes.xCoord, 2000000)) + SQUARE(" & y & " - ISNULL(tbl_Postcodes.yCoord, 200000))) / 1000 * 0.62 AS Int) AS Dist " & _
                  "FROM v2_dealers INNER JOIN v2_dealerbrands ON v2_dealers.ID=v2_dealerbrands.dealer LEFT OUTER JOIN tbl_Postcodes ON v2_dealers.Postcode=tbl_Postcodes.PC "& _
                  "left join tbl_rvlibrary on v2_dealerbrands.make=tbl_rvlibrary.make " & _
                  "WHERE v2_dealers.status='OK' and v2_dealers.id in (select ds.dealer from v2_dealersites ds,v2_sites s where s.id=ds.site and url='"&thissite&"') " & _
                  "and tbl_rvlibrary.rvid='" & rvID & "' " & _
                  "AND (SQRT(SQUARE(" & x & "- ISNULL(tbl_Postcodes.xCoord, 2000000)) + SQUARE(" & y & " - ISNULL(tbl_Postcodes.yCoord, 200000))) / 1000 * 0.62 <=150)" & _
                  " ORDER BY Dist

And my attempt of the mysql:

SELECT DISTINCT(v2_dealers.ID), name, town, County, CAST(SQUARE('$x' IS NULL(tbl_postcodes.xCoord, 2000000)) + SQUARE('$y' IS NULL(tbl_postcodes.yCoord, 200000)) / 1000 * 0.62 AS Int) AS Dist
                  FROM v2_dealers INNER JOIN v2_dealerbrands ON v2_dealers.ID=v2_dealerbrands.dealer LEFT OUTER JOIN tbl_Postcodes ON v2_dealers.Postcode=tbl_Postcodes.PC
                  left join tbl_rvlibrary on v2_dealerbrands.make=tbl_rvlibrary.make
                  WHERE v2_dealers.status='OK' and v2_dealers.id in (select ds.dealer from v2_dealersites ds,v2_sites s where s.id=ds.site and url='$thissite')
                  and tbl_rvlibrary.rvid='$rvID'
                  AND (SQRT(SQUARE('$x' IS NULL(tbl_postcodes.xCoord, 2000000)) + SQUARE('$y' IS NULL(tbl_postcodes.yCoord, 200000))) / 1000 * 0.62 <=150)
                  ORDER BY Dist


This is the error I receive:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'IS NULL(tbl_postcodes.xCoord, 2000000)) + SQUARE(792660 - IS NULL(tbl_postcodes.' at line 1

I have tried using IF NULL but still receive the same error.
0
Comment
Question by:cyberswannie
  • 3
  • 2
5 Comments
 
LVL 143

Accepted Solution

by:
Guy Hengel [angelIII / a3] earned 125 total points
ID: 33483737
in MySQL, the function IsNull is not doing the same thing as in MS SQL Server.
use COALESCE instead

SELECT DISTINCT(v2_dealers.ID), name, town, County, CAST(SQUARE('$x' - COALESCE(tbl_postcodes.xCoord, 2000000)) + SQUARE('$y'   - COALESCE(tbl_postcodes.yCoord, 200000)) / 1000 * 0.62 AS Int) AS Dist
                  FROM v2_dealers INNER JOIN v2_dealerbrands ON v2_dealers.ID=v2_dealerbrands.dealer LEFT OUTER JOIN tbl_Postcodes ON v2_dealers.Postcode=tbl_Postcodes.PC
                  left join tbl_rvlibrary on v2_dealerbrands.make=tbl_rvlibrary.make
                  WHERE v2_dealers.status='OK' and v2_dealers.id in (select ds.dealer from v2_dealersites ds,v2_sites s where s.id=ds.site and url='$thissite')
                  and tbl_rvlibrary.rvid='$rvID'
                  AND (SQRT(SQUARE('$x' - COALESCE(tbl_postcodes.xCoord, 2000000)) + SQUARE('$y' - COALESCE(tbl_postcodes.yCoord, 200000))) / 1000 * 0.62 <=150)
                  ORDER BY Dist

Open in new window

0
 

Author Comment

by:cyberswannie
ID: 33483803
Thanks AngelIII, 1 for the quick reply and 2 for sorting the IS NULL problem, Unfortuneatly now I receice this error:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Int) AS Dist FROM v2_dealers INNER JOIN v2_dealerbrands ON v2_dealers.ID=v2_d' at line 1

Thanks again for the help, I have never even seen the function COALESCE.
0
 
LVL 143

Assisted Solution

by:Guy Hengel [angelIII / a3]
Guy Hengel [angelIII / a3] earned 125 total points
ID: 33483927
it must be INTEGER and not INT:
http://dev.mysql.com/doc/refman/5.0/en/cast-functions.html#function_cast
SELECT DISTINCT(v2_dealers.ID), name, town, County
, CAST( SQUARE('$x' - COALESCE(tbl_postcodes.xCoord, 2000000))  
        + SQUARE('$y'   - COALESCE(tbl_postcodes.yCoord, 200000)) / 1000 * 0.62 AS Integer) AS Dist

FROM v2_dealers 
INNER JOIN v2_dealerbrands ON v2_dealers.ID=v2_dealerbrands.dealer 
LEFT OUTER JOIN tbl_Postcodes ON v2_dealers.Postcode=tbl_Postcodes.PC
left join tbl_rvlibrary on v2_dealerbrands.make=tbl_rvlibrary.make

WHERE v2_dealers.status='OK' 
  and v2_dealers.id in (select ds.dealer from v2_dealersites ds,v2_sites s where s.id=ds.site and url='$thissite')
  and tbl_rvlibrary.rvid='$rvID'
  AND (SQRT(SQUARE('$x' - COALESCE(tbl_postcodes.xCoord, 2000000)) + SQUARE('$y' - COALESCE(tbl_postcodes.yCoord, 200000))) / 1000 * 0.62 <=150)
ORDER BY Dist

Open in new window

0
 

Author Closing Comment

by:cyberswannie
ID: 33483993
Quick and correct couldn't of asked for any more.
0
 

Author Comment

by:cyberswannie
ID: 33483996
Thanks Angellll
0

Featured Post

Free Tool: Path Explorer

An intuitive utility to help find the CSS path to UI elements on a webpage. These paths are used frequently in a variety of front-end development and QA automation tasks.

One of a set of tools we're offering as a way of saying thank you for being a part of the community.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Ever needed a SQL 2008 Database replicated/mirrored/log shipped on another server but you can't take the downtime inflicted by initial snapshot or disconnect while T-logs are restored or mirror applied? You can use SQL Server Initialize from Backup…
When table data gets too large to manage or queries take too long to execute the solution is often to buy bigger hardware or assign more CPUs and memory resources to the machine to solve the problem. However, the best, cheapest and most effective so…
Viewers will learn how the fundamental information of how to create a table.
Viewers will learn how to use the INSERT statement to insert data into their tables. It will also introduce the NULL statement, to show them what happens when no value is giving for any given column.

856 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question