Go Premium for a chance to win a PS4. Enter to Win

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 668
  • Last Modified:

Transform xml address as CDATA

I am using xsl to transform an xml file.  It contains an address.  This address could contain unsuitable characters eg &.  I want to output the address within CDATA.
e.g <![CDATA[Smith & Co]]>
How can Ii code this in the xsl?  Obviously the coding below does not process anything within the CDATA.  
<addr>
                <xsl:text><![CDATA[</xsl:text>
                <xsl:value-of select="AR/AR_Addr1"/>
                <xsl:text>]]></xsl:text>
              </addr>

Open in new window

0
Nigel Keith-Walker
Asked:
Nigel Keith-Walker
  • 3
  • 2
1 Solution
 
grepllCommented:
First, you don't have to bother whether there is CDATA section in the output, the & and other special chars will be always escaped correctly in the output file.

If you really want to have a CDATA section there, use attribute cdata-section-elements of xsl:output. See example below. If you need more elements generated using CDATA, put them there separeted by spaces, e.g. cdata-section-elements="addr email"
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" cdata-section-elements="addr"/>

<xsl:template match="/">
	<addr>
		<xsl:text>Smith &amp; Co</xsl:text>
	</addr>
</xsl:template>

</xsl:stylesheet>

Open in new window

0
 
Nigel Keith-WalkerAuthor Commented:
So that I should not have to use CDATA to output addres information, because it will automatically replace unusual characters wuth &lt etc.

The alternative would be to set up matches for the adress line.  Since I have a few lines, would this mean individual matches?
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" cdata-section-elements="addr1" "addr2" "addr3"/>

<xsl:template match="/">
	<addr1>
		<xsl:value-of select="AR/AR_Addr1"/>
	</addr1>
</xsl:template>
<xsl:template match="/">
	<addr2>
		<xsl:value-of select="AR/AR_Addr2"/>
	</addr2>
</xsl:template>
<xsl:template match="/">
	<addr3>
		<xsl:value-of select="AR/AR_Addr3"/>
	</addr3>
</xsl:template>

</xsl:stylesheet>

Open in new window

0
 
grepllCommented:
> So that I should not have to use CDATA to output addres information, because it will automatically replace unusual characters wuth &lt etc.

Exactly. You can use CDATA - for example when you expect to do hand editing of the output documen - but you really don't have to.

> The alternative would be to set up matches for the adress line.  Since I have a few lines, would this mean individual matches?

Whenever you want to generate CDATA section in XSLT, you have to add desired element is cdata-section-elements. In your case it would be

cdata-section-elements="addr1 addr2 addr3"
(but not cdata-section-elements="addr1" "addr2" "addr3")

The rest is normal XSLT workflow, but the code you posted not correct.

I don't know what data you are transforming and what is the desired output. Probably you ment something like this (see below). However, that's no more matter of generating CDATA sections, so I'd suggest you to post new question if you have further issues regarding XSLT in general.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" cdata-section-elements="addr1 addr2 addr3"/>

<xsl:template match="/">
        <addr1>
                <xsl:value-of select="AR/AR_Addr1"/>
        </addr1>
        <addr2>
                <xsl:value-of select="AR/AR_Addr2"/>
        </addr2>
        <addr3>
                <xsl:value-of select="AR/AR_Addr3"/>
        </addr3>
</xsl:template>

</xsl:stylesheet>

Open in new window

0
 
Nigel Keith-WalkerAuthor Commented:
Apologies - I thought that I had acceppted this a few days ago - but must have failed to submit/save the response.  I have removed the CDATA and the & is translated to &amp.
0
 
grepllCommented:
Glad to hear that you solved it.

While looking at my previous post, one note for the record: Any XML document must have exactly one root tag, I forgot to put it in the output document. Apology for the mistake.
<xsl:template match="/">
    <addresses>
        <addr1>
            <xsl:value-of select="AR/AR_Addr1"/>
        </addr1>
        <addr2>
            <xsl:value-of select="AR/AR_Addr2"/>
        </addr2>
        <addr3>
            <xsl:value-of select="AR/AR_Addr3"/>
        </addr3>
    </addresses>
</xsl:template>

Open in new window

0

Featured Post

Independent Software Vendors: We Want Your Opinion

We value your feedback.

Take our survey and automatically be enter to win anyone of the following:
Yeti Cooler, Amazon eGift Card, and Movie eGift Card!

  • 3
  • 2
Tackle projects and never again get stuck behind a technical roadblock.
Join Now