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jquery display hidden elements

Hello experts

I am trying to do the following. After you select an item under #type-shirts, the next menu option (#types-shirt)is suppose to display (it is set to none on the style sheet), but my code is just not working. Can someone please guide me?

thanks in advance.

html:
      <p id="types-shirts">
            <select>
                  <option value="">Select type shirt</option>
                  <option value="1">1</option>
                  <option value="2">2</option>
                  <option value="3">3</option>
                  <option value="4">4</option>
            </select>
      </p>
      <p id="types-pants"> //this one has a style: display:none
            <select>
                  <option value="">Select type pants</option>
                  <option value="1">1</option>
                  <option value="2">2</option>
                  <option value="3">3</option>
                  <option value="4">4</option>
            </select>
      </p>

js:
            if ($('#types-shirts').val() != ''){
                  $("#types-pants").css("display","block");
            }

leakim971

You may check the option value :

$("#types-shirts").change(function() {
			$("option[value!='']", "#types-shirts").is(":selected")?$("#types-pants").show():$("#types-pants").hide();
		});

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leakim971

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glepiza

ASKER

oh wow, that was quick. I am learning a lot here, I was looking at so many functions and never saw CHANGE. that is a great one.

Thanks so much.

leakim971