Solved

# Numeric if statment not generating desired results

Posted on 2010-08-25
302 Views
Experts,
When given 2 numbers, I'd like to determine the "favorite" (for betting).  The Favorite is the NEGATIVE number.  So the team with a spread of "-7" is the favorite and the underdog's spread is "7".

When I output the home and visiting spreads:
I get:
13.5
-13.5
So clearly, one is negative and one is positive, and therefore less than the other.

When I run the following if statement:

// Option 1
\$FAV =       \$teamname[1];
\$UDOG = \$teamname[0];
}
// Option 2
\$FAV = \$teamname[0];
\$UDOG = \$teamname[1];
}
else{
// Option 3
\$FAV =       \$teamname[1];
\$UDOG = \$teamname[0];
// Spread of 0 means teams are EVEN.
}
}

The above statement Outputs Option 1 EVERY TIME.
In cases when Option 2 should be true, it still results in #1.
I know this is incorrect, because the \$SPREAD appears as a positive number
This shouldn't be possible because the negative number should ALWAYS be less than the positive, becoming the \$SPREAD.

example of incorrect result:
-3
3

Favorite: Virginia Tech
Underdog: Boise State

Visiting: Boise State -3
Home: Virginia Tech 3

The Favorite should be Boise State since it's spread is -3.
It's outputting 3 as the spread, telling me it believes option 1 in the if statement is true.

Any ideas?
0
Question by:dsg138
• 7
• 4
• 2

LVL 11

Expert Comment

ID: 33528152
for less than checking it will be one < and no <<

so it will be like

// Option 1
\$FAV =       \$teamname[1];
\$UDOG = \$teamname[0];
}
// Option 2
\$FAV = \$teamname[0];
\$UDOG = \$teamname[1];
}
else{
// Option 3
\$FAV =       \$teamname[1];
\$UDOG = \$teamname[0];
// Spread of 0 means teams are EVEN.
}
}
0

LVL 11

Expert Comment

ID: 33528156
you can check more about php operators at http://php.net/manual/en/language.operators.comparison.php
0

Author Comment

ID: 33528192
Thanks.
I initially tried that and it didn't work either.
When I use just one < or > like in your example, it results in Option 3 every time which is the "else" clause.

Not sure what it could be...
My other thought was perhaps the problem was with the numbers and not the syntax.
Maybe it didn't think those values were numeric?
So I added this before the loop, but still results in Option 3 for everything.
0

LVL 11

Expert Comment

ID: 33528205
try this
``````if (\$home_spread<\$vis_spread){

// Option 1

\$FAV =       \$teamname[1];

\$UDOG = \$teamname[0];

}

// Option 2

\$FAV = \$teamname[0];

\$UDOG = \$teamname[1];

}

else{

// Option 3

\$FAV =       \$teamname[1];

\$UDOG = \$teamname[0];

// Spread of 0 means teams are EVEN.

}

}

``````
0

LVL 11

Expert Comment

ID: 33528208
also there is one extra } at the end of the code... not sure if that's for any prev if clause...
0

Author Comment

ID: 33530412
Thanks.  The end } is from a higher loop and should be correct.
I tried your code and it results in Option 3 (the else clause) for EVERY instance.

That's the part that has me confused.
It seems unable to compare the 2 numbers, even though it has no problems outputting them.
0

LVL 11

Expert Comment

ID: 33530481
try comparing numbers using this way...
http://www.phpbuilder.com/manual/function.gmp-cmp.php
0

LVL 30

Assisted Solution

Marco Gasi earned 100 total points
ID: 33530784
I followed the discussion and I tested the code posted by rdonline1 (ID:33528205). To test I've lttle changed, adding manually variables value and maybe I don't understood your explanation, dsg138, but it seems to work: my output is not 3 but -3. The code I've tested is posted in the snippet below: perhaps this test can help you to find the problem...
``````<?php
\$teamname[0] = 'Virginia Tech';
\$teamname[1] = 'Boise State';
\$Option = 1;
\$FAV = \$teamname[1];
\$UDOG = \$teamname[0];
}
\$Option = 2;
\$FAV = \$teamname[0];
\$UDOG = \$teamname[1];
}
else{
\$Option = 3;
\$FAV = \$teamname[1];
\$UDOG = \$teamname[0];
// Spread of 0 means teams are EVEN.
}

echo "Favourite is \$FAV<br>";
echo "Underdog is \$UDOG<br>";
echo "Option n. \$Option";
?>
``````
0

Author Comment

ID: 33538180
Thanks all for the feedback...

I think the issue is with my numbers:
When I hard code the numbers below like in the code above, everything works correctly:

My numbers are coming from here through XML parsing:

Here is the XML file:
http://xml.pinnaclesports.com/pinnacleFeed.aspx?sportType=Football&sportsubtype=NCAA

And here's where the "-13" and "13" come from...

13.5
-13.5

So when I hardcode the numbers in they work, but pulling them from the XML doesn't work...

Any other ideas?
0

LVL 11

Accepted Solution

Rajesh Dalmia earned 400 total points
ID: 33538707
try as

0 addition will make sure that the variables are in integer...
0

Author Closing Comment

ID: 33538739
That did it!  Perfect!

rdonline1, thanks for the code that fixed the issue.

marqusG, thanks for the testing code that led me to realize that it wasn't considering those fields as integers.

Thanks,

-Dan

0

LVL 11

Expert Comment

ID: 33538742
thanks dan, gald to help...
0

LVL 30

Expert Comment

ID: 33539280
Thank you for points, dan. Have a nice day.
0

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