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how do you calculate the last page of results in a list

Posted on 2010-08-27
2
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Last Modified: 2012-05-10
I'm trying to calculate the first and last page of records in a list.  For example, if the returned list contained 100 records and page could display 10 records per page, I am trying to create a method to grab the first 10 records for a link that would take the user to the first 10 records in the list and then another link "last" that would take the user to the last 10 records in the list.

I have an existing method that takes the user to the next and previous set of records (see code below).  How can I get the first and last pages?

This relates to Salesforce apex programming, but I'm asking in the .net and c# zones because the logic should be similar.

Thanks for any help.
/* getlistContact returns the list of Contacts upto 10 per page implementing pagination*/    
    Public List<Contact> getlistContact()
    {
      return contactList_Next ;
    }
    
    /*  Previous method has the logic for displaying the list of Next contacts from Contact object implementing pagination*/ 
    Public void Next()
    { 
        try
        {
            showprev = true;
            contactList_Next.clear();
            Integer limit1 = 0;
  
            if(next+countPerPage < contactList.size())
                limit1 = next+countPerPage;
            else
            {
                limit1 = contactList.size();
                shownext = false;
            }
                
            for(Integer i=next; i<limit1; i++)
            contactList_Next.add(contactList[i]);
    
            Next+=countPerPage;
            
        }catch(Exception e){system.debug('Exception :'+e);}
    }
    
  /*  Previous method has the logic for displaying the list of previous contacts from Contact object implementing pagination*/    
    Public void Prev()
    {
        try
        {
            shownext = true;
            contactList_Next.clear();
            Integer limit1 = 0;        
            if(next-(countPerPage+countPerPage) > 0)
                limit1 = next-countPerPage;
            else
            {
                limit1 = next-countPerPage; 
                showprev = false;
            }
    
            for(Integer i=next-(countPerPage+countPerPage); i<limit1; i++)    
            contactList_Next.add(contactList[i]);
            Next-=countPerPage; 
        }catch(Exception e){
          system.debug('Exception :'+e);
        }               
    }

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Question by:-Dman100-
2 Comments
 
LVL 6

Accepted Solution

by:
DalHorinek earned 250 total points
ID: 33544909
If you want last 10 items in a list, then do this in pseudocode

limit = 10;
list_size = list.size(); // size of the list
index = list_size - limit -1 // index where to start (size of the list - limit and -1 (cuz indexing starts at zero, we know)

result = new List; // new list
for (i = index; i != list_size; i++)
      result.push(list[i]); // push last 10 items into new list

return result; // return it

But I'm not sure If I have understood correctly.
0
 
LVL 16

Assisted Solution

by:SriVaddadi
SriVaddadi earned 250 total points
ID: 33545018

Add "using System.Linq;"

Below code gives you the last 10 records

  List<Contact> list = new List<Contact>();
            Contact[] lastPage = new Contact[10];
            list.CopyTo(list.Count-10, lastPage, 0, 10);
            List<Contact> lastPageList = lastPage.ToList<Contact>();
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