Powershell - "open with" equal
Posted on 2010-08-28
I have several XML files that are encrypted and require opening with a specific application. I would like to use powershell to:
1. open the file in the specific application
2. save the file as txt or xml
3. parse the file using XML controls.
I will address step 3 later. 1 and 2 is where I could use some help. Is there a switch or bar I could add to a get cmdlet to specify an application to access a file with?
The application I need to use is not an installed app. It is a single exe file.