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C++: strcmp - how does it work?

Why is it that when you put !str.compare() it actually works? Doesn't the "!" actually mean false?

From my understanding, compare() checks every letter in the string and uses a counter to track if there are any differences. If the number returned is 0 then the string matches, anything else means that the string is not the same

In C++, 0 = true, and 1 = false (unless I'm mistaken) so why does the "!" if statement and the "== 0" if statement both work?
#include <iostream>
#include <string>
using namespace std;

int main()
{
  string str = "test";

  // if statement with !str.compare()
  if (!str.compare("test"))
     cout << "String Matched!" << endl;

  // if statement with == 0 str.compare()
  if (str.compare("test") == 0)
     cout << "String Matched!" << endl;

  return 0;
}

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Zenoture
Asked:
Zenoture
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1 Solution
 
ozoCommented:
==0 is false, != 0 is true
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ZenotureAuthor Commented:
well then that's why then lol. Thank you.
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phoffricCommented:
>> In C++, 0 = true, and 1 = false (unless I'm mistaken)
C++ takes its definition of integer numeric values of true/false from C:
     false is 0
     true is not 0
===========
So, consider following if else statement (either C or C++):
    if( x ) {
        // do if x != 0
    }
    else {
        // do if x == 0
    }
===========

Only if x is 0 is the else body executed; for all other integers, the x != 0 body is executed.
===========
However, some functions return 0 which may or may not mean true. You have to read the api of the function to understand what the return value means.

See string::compare:
    http://www.cplusplus.com/reference/string/string/compare/

The return value of compare is "0 if the compared characters sequences are equal". This is not saying that a 0 means true, just that the sequences are equal.

  if (!str.compare("test"))
     cout << "String Matched!" << endl;
is equivalent to (my preferred way):
  if ( 0 == str.compare("test") ) // is str == "test"
     cout << "String Matched!" << endl;

===========
compare returns an int, so the first paragraph applies here. Since a 0 return value means that str == "test", and since 0 in a if test condition means false, then the ! (NOT) unary operator on 0 means NOT false, which is true.

===========
See section "Logical operators" in
       http://www.cplusplus.com/doc/tutorial/operators/

"The Operator ! is the C++ operator to perform the Boolean operation NOT, it has only one operand, located at its right, and the only thing that it does is to inverse the value of it, producing false if its operand is true and true if its operand is false. Basically, it returns the opposite Boolean value of evaluating its operand. For example:"
!(5 == 5) // is false since the expression at its right (5==5) is true
!(6 <= 4) // evaluates to true because (6 <= 4) would be false
!true    // evaluates to false
!false   // evaluates to true

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ZenotureAuthor Commented:
Oh... so i was wrong... but now the whole 0/1 true/false thing makes sense haha. Thanks a lot phoffric, you never cease to amaze me =)
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phoffricCommented:
Isn't it great when things make sense!
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ZenotureAuthor Commented:
Of course! Thought why other languages tend to flip the meaning, I'll never understand...

It can't be THAT hard to stick to one standard can it? lol
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ZenotureAuthor Commented:
though*
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phoffricCommented:
C++ was created in order to guarantee job security, so the standard had to be different. Here is the confession from the creator of C++.
    http://www.odgaard.org/jeod/funny/interview.html
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