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Ajax Tab Control Disappears when using the OnClientActiveTabChanged Property

Scenario:
I am using the AJAX TabControl and have some javascript to control the ActiveTabIndex on postback as I have some Dropdowns in each tab that cause it to revert back to index 0.   So I added some javascript to control this and call it by setting the OnClientActiveTabChanged Property on the Tab Control.  As soon as I do that and run the debugger to test the Entire Tab Control disappears.  For some reason by setting this property cause the control not to be rendered in the browser.   Need some help in finding out why so I can test to see if this javascript will work.  

Here is My Code:

Tab Control:
<cc1:TabContainer ID="TabContainerAdmin" runat="server" OnClientActiveTabChanged="SaveActiveTabIndex" ActiveTabIndex="0" Enabled="true">
        <cc1:TabPanel ID="TabPanelCircuit" runat="server" HeaderText="Manage Circuit Data">

JavaScript

<script type="text/javascript">
function SaveActiveTabIndex(sender, e)
{
var activetabindex = sender.get_activeTab().get_tabIndex();
setCookie(activetabindex);
}
function setCookie(value)
{
document.cookie = “tabIndex=” + escape(value) ;
}

</script>

Code Behind Function called on PageLoad Event

protected void ChangeTabIndex()
    {
        if (Request.Cookies["tabIndex"] != null)
        {
            int index = int.Parse(Server.HtmlEncode(Request.Cookies["tabIndex"].Value));

            if (index > -1 && index < TabContainerAdmin.Tabs.Count)

            {
                TabContainerAdmin.ActiveTabIndex = index;
            }

            else
            {
                TabContainerAdmin.ActiveTabIndex = 0;
            }
        }
    }

0
jholmes0724
Asked:
jholmes0724
1 Solution
 
masterpassCommented:
TabContainerAdmin.ActiveTabIndex has both get and set

so , I think, there is no need for you to store the tab index in the cookie, you can get the active tabindex in the page load by

TabContainerAdmin.ActiveTabIndex
0
 
jholmes0724Author Commented:
Yes I did come to that conclusion as well.  Thanks for responding.
0
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