asked on

Add styles like vertical-align and max-column-width to XSLT

Dear Experts,

I have an XmlDocument that I am generating dynamically based on a query to a SQL server database. I am exporting the result to a Excel file with the following code.

DataTable dataTable = GetPosts();
XmlDocument xmlDoc = BuildXml(dataTable);
String fileName;
fileName = lblFormCode.Text + "_Export_" + String.Format("{0:MM_dd_yyyy}", _startDate) + "_To_" + String.Format("{0:MM_dd_yyyy}", _endDate);
if (fileName.IndexOfAny(System.IO.Path.GetInvalidFileNameChars()) != -1)
{
fileName = "Form_Export_From" + "_" + String.Format("{0:MM_dd_yyyy}", _startDate) + "_To_" + String.Format("{0:MM_dd_yyyy}", _endDate);
}
//Create the FileStream to write with.
MemoryStream memStream = new MemoryStream();
//Create an XmlTextWriter for the FileStream.
XmlTextWriter xtw = new XmlTextWriter(memStream, System.Text.Encoding.Unicode);
//Transform the XML using the stylesheet.
XslCompiledTransform trans = new XslCompiledTransform();
XsltArgumentList arguments = new XsltArgumentList();
trans.Load(Server.MapPath("XSL.xsl"));
Response.Clear();
Response.AddHeader("Content-disposition", "attachment; filename=" + fileName + ".xls");
Response.ContentType = "application/vnd.ms-excel";
trans.Transform(xmlDoc, arguments, Response.OutputStream);
Response.End();

PROBLEM:
I have an XLST stylesheet that I have pasted below. I need the vertical alignment of every column to be at the top. I need column widths and heights to be auto, and headers to be bold. I would like an alternating row color (any color, I can change it later). Finally, I have two columns (Recipe Ingredients, and Instructions) that can get quite lengthy. I went through some trouble to preserve the users page breaks in the XML. Right now, those page breaks are not being shown.

Any help would be appreciated

<xsl:stylesheet version="1.0"
xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:user="urn:my-scripts"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet" >

<xsl:template match="/">
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:o="urn:schemas-microsoft-com:office:office"
xmlns:x="urn:schemas-microsoft-com:office:excel"
xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
xmlns:html="http://www.w3.org/TR/REC-html40">
<xsl:apply-templates/>
</Workbook>
</xsl:template>

<xsl:template match="/*">
<Worksheet>
<xsl:attribute name="ss:Name">
<xsl:value-of select="local-name(/*/*)"/>
</xsl:attribute>
<Table x:FullColumns="1" x:FullRows="1">
<Row>
<xsl:for-each select="*[position() = 1]/*">
<Cell>
<xsl:attribute name="bcolor"></xsl:attribute>
<Data ss:Type="String">
<xsl:value-of select="local-name()"/>
</Data>
</Cell>
</xsl:for-each>
</Row>
<xsl:apply-templates/>
</Table>
</Worksheet>
</xsl:template>

<xsl:template match="/*/*">
<Row>
<xsl:apply-templates/>
</Row>
</xsl:template>

<xsl:template match="/*/*/*">
<Cell>
<Data ss:Type="String">
<xsl:value-of select="."/>
</Data>
</Cell>
</xsl:template>

</xsl:stylesheet>

Thanks in advance!!!!!

ASKER CERTIFIED SOLUTION

kmartin7

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kmartin7

So I made a quick change to your XSLT that will make each cell default to "Top":

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns="urn:schemas-microsoft-com:office:spreadsheet" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:user="urn:my-scripts" xmlns:o="urn:schemas-microsoft-com:office:office"
                xmlns:x="urn:schemas-microsoft-com:office:excel" xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet">
	<xsl:output indent="yes"/>

	<xsl:template match="/">
		<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:x="urn:schemas-microsoft-com:office:excel" xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
		          xmlns:html="http://www.w3.org/TR/REC-html40">
				  <Styles>
			<Style ss:ID="Default" ss:Name="Normal">
				<Alignment ss:Vertical="Top"/>
				<Borders/>
				<Font/>
				<Interior/>
				<NumberFormat/>
				<Protection/>
			</Style>
		</Styles>
			<xsl:apply-templates/>
		</Workbook>
	</xsl:template>


	<xsl:template match="/*">
		<Worksheet>
			<xsl:attribute name="ss:Name">
				<xsl:value-of select="local-name(/*/*)"/>
			</xsl:attribute>
			<Table x:FullColumns="1" x:FullRows="1">
				<Row>
					<xsl:for-each select="*[position() = 1]/*">
						<Cell>
							<xsl:attribute name="bcolor"></xsl:attribute>
							<Data ss:Type="String">
								<xsl:value-of select="local-name()"/>
							</Data>
						</Cell>
					</xsl:for-each>
				</Row>
				<xsl:apply-templates/>
			</Table>
		</Worksheet>
	</xsl:template>


	<xsl:template match="/*/*">
		<Row>
			<xsl:apply-templates/>
		</Row>
	</xsl:template>


	<xsl:template match="/*/*/*">
		<Cell>
			<Data ss:Type="String">
				<xsl:value-of select="."/>
			</Data>
		</Cell>
	</xsl:template>
</xsl:stylesheet>

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bickes0724

ASKER

Thank you! That is working now. I am going to keep working on the rest...

kmartin7

If I have answered to your satisfaction, please accept and grade my answer.

Thanks!

kmartin7