SQL - Nesting two functions (SELECT DISTINCT and SUM)

Posted on 2010-09-01
Last Modified: 2012-06-21

I have 2 SQL statements I want to nest yet I can't seem to be able to find the right combination

I want the sum of all the products called "Spots" from tblSurvey. I have the sql to give me the sum.

SELECT SUM(A.Volume) AS ["Total Sales"]
FROM tblSurvey AS A
WHERE A.Product='Spots';

I have another statement that gives me the product using the SELECT DISTINCT

FROM tblSurvey AS B
WHERE (((B.Product)='Spots'));

I thought I could combine the two with something like

SELECT SUM(A.Volume) AS "Total Sales"
FROM tblSurvey AS A
              FROM tblSurvey as B
              WHERE B.[Product] = 'Spots');

Except this sums all the numbers in the table (not using the WHERE criteria).

I tried using this method

SELECT  DISTINCT A.[Product], Sum(A.Volume) as "Total Sales",
FROM (SELECT B.[Product], B.[Volume]
              FROM tblSurvey as B
              WHERE B.[Product] = 'Spots') AS A;

But that produced an error. I'm pretty sure SELECT DISTINCT and the SUM Function can't be on the same statement, does anyone know how to achieve the desired result?

Product Total Sales
Spots    some #


Question by:Shino_skay
LVL 12

Accepted Solution

mcv22 earned 250 total points
ID: 33580519
      SUM(Volume) AS [Total Sales]
      Product = 'Spots'
LVL 11

Assisted Solution

by:Missus Miss_Sellaneus
Missus Miss_Sellaneus earned 250 total points
ID: 33580560
I'm not entirely sure what you're trying to accomplish. Is this what you needed?

SELECT product, SUM(volume) AS "Total Sales" FROM tblSurvey WHERE product='Spots' GROUP BY product ORDER BY product;

Author Comment

ID: 33580832
Silly me, that's for pointing out the GROUP BY clause which eliminates the distinct. Thanks you two.

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