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SQL SUM

Posted on 2010-09-01
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Last Modified: 2012-05-10
Hi  Experts ,

In this attached code , i want am getting desired output, but i want sum as well . How do i go about it.
SELECT count(*), (
case
when PICSTATUS = '11' then 'Transfer Rejected'
when picstatus = '12' then 'Transfer Cancelled'
when picstatus = '20' then 'New Sale'
when picstatus = '70' then 'Pricing Accepted'
when picstatus = '72' then 'Sale Confirmed'
when picstatus = '80' then 'Ready for Transfer'
when picstatus = '90' then 'Transfer in progress'
end
) as STATUS FROM PROCONSUMER WHERE PICSTATUS NOT IN (100,10) GROUP BY PICSTATUS "

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Question by:santoshmotwani
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6 Comments
 
LVL 61

Expert Comment

by:Kevin Cross
ID: 33582699
What column do you need to SUM?

Also, this is in both MySQL and SQL Server: which one are you using ?
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LVL 61

Expert Comment

by:Kevin Cross
ID: 33582706
Anyway, for whichever column:

(note you can simplify case to -- case PICSTATUS when '11' then 'Transfer Rejected' when '12' ...)


SELECT count(*), sum(some_column), (
case
when PICSTATUS = '11' then 'Transfer Rejected'
when picstatus = '12' then 'Transfer Cancelled'
when picstatus = '20' then 'New Sale'
when picstatus = '70' then 'Pricing Accepted'
when picstatus = '72' then 'Sale Confirmed'
when picstatus = '80' then 'Ready for Transfer'
when picstatus = '90' then 'Transfer in progress'
end
) as STATUS 
FROM PROCONSUMER 
WHERE PICSTATUS NOT IN (100,10) 
GROUP BY PICSTATUS "

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0
 
LVL 16

Author Comment

by:santoshmotwani
ID: 33582828
server is MSSQL server 2005, This query returns output something like

Transfer Rejected47
 Transfer Cancelled19
 New Sale1632

 Pricing Accepted639
 Sale Confirmed20
 Ready for Transfer1
 Transfer in progress1725


m doing this in perl.

i want to total of all the number that come in output.

mwvisa1 - Can you please help me simply & sum above query plz

Cheers
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LVL 61

Expert Comment

by:Kevin Cross
ID: 33583000
For SQL 2005, try with an analytical function and empty over() clause.  You called it sum so showed with sum(1) which will be same as count(*) of all rows (i.e., you could use count(*) over() - or - count(1) over())
SELECT count(*), sum(1) over(), (
case
when PICSTATUS = '11' then 'Transfer Rejected'
when picstatus = '12' then 'Transfer Cancelled'
when picstatus = '20' then 'New Sale'
when picstatus = '70' then 'Pricing Accepted'
when picstatus = '72' then 'Sale Confirmed'
when picstatus = '80' then 'Ready for Transfer'
when picstatus = '90' then 'Transfer in progress'
end
) as STATUS 
FROM PROCONSUMER 
WHERE PICSTATUS NOT IN (100,10) 
GROUP BY PICSTATUS "

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0
 
LVL 61

Accepted Solution

by:
Kevin Cross earned 2000 total points
ID: 33583014
Sorry that will give you count of the different groups, so that is not what you want -- try this:
SELECT count(*), (
case
when PICSTATUS is null then 'Totals'
when PICSTATUS = '11' then 'Transfer Rejected'
when picstatus = '12' then 'Transfer Cancelled'
when picstatus = '20' then 'New Sale'
when picstatus = '70' then 'Pricing Accepted'
when picstatus = '72' then 'Sale Confirmed'
when picstatus = '80' then 'Ready for Transfer'
when picstatus = '90' then 'Transfer in progress'
end
) as STATUS 
FROM PROCONSUMER 
WHERE PICSTATUS NOT IN (100,10) 
GROUP BY PICSTATUS WITH ROLLUP"

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0
 
LVL 16

Author Closing Comment

by:santoshmotwani
ID: 33583630
Thanks , it solved my issue
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