How do I calculate quartiles in MSSQL

How do I calculate a quartile in mssql (1st quartile, 2nd quartile, etc..)?
I have attached an excel sheet with 57 rows and showing what the 1st ,2nd 3rd and 4th quartile should be
Assume I have those 57 rows in mssql table
How do I get the same number from an mssql query?
Ideally I would run a query against teh database table and the result will be a table with 4 rows
(1st,2nd,3rd, and 4th quartile with their values)
Thank you

Book1.xls
LVL 9
xav056Asked:
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cyberkiwiConnect With a Mentor Commented:
;with tmp as (
      select n, qt=NTILE(4) over (order by n), rn=ROW_NUMBER() over (order by n)
      from quartile_test)
select n
from tmp
where rn in (select MAX(rn) from tmp group by qt)


Quartile_test should be the name of your table, n is the column name.
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
I presume you want this:
with min_max as ( 
  select min(yourfield) n
       , max(yourfield) x
       , ( max(yourfield) - min(yourfield)  ) / 4 q 
       , min(yourfield) + 1 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q1
       , min(yourfield) + 2 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q2
       , min(yourfield) + 3 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q3
from yourtable)
select min(case when yourfield >= q1 then yourfield) Q1
     , min(case when yourfield >= q2 then yourfield) Q2
     , min(case when yourfield >= q3 then yourfield) Q3
     , min(case when yourfield >= x then yourfield) Q4
  from yourtable

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xav056Author Commented:
getting a syntax error
q1, q2 .. in the second block
I guess because q1 q2 are in min_max
I am not sue how to fix it
thanks
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Guy Hengel [angelIII / a3]Billing EngineerCommented:
yes, indeed, sorry for that
with min_max as ( 
  select min(yourfield) n
       , max(yourfield) x
       , ( max(yourfield) - min(yourfield)  ) / 4 q 
       , min(yourfield) + 1 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q1
       , min(yourfield) + 2 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q2
       , min(yourfield) + 3 * ( ( max(yourfield) - min(yourfield)  ) / 4 ) q3
from yourtable)
select min(case when yourfield >= q1 then yourfield) Q1
     , min(case when yourfield >= q2 then yourfield) Q2
     , min(case when yourfield >= q3 then yourfield) Q3
     , min(case when yourfield >= x then yourfield) Q4
  from yourtable
  cross join min_max 

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xav056Author Commented:
I am getting
39.314516      59.208731        84.942085                          100.000000
instead of
39.9103139      53.6809816       92.28855721       100
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cyberkiwiCommented:
Were you referring to http:#a33610329?
With your data (Excel), it gives me

39.9103139013452
53.680981595092
92.2885572139303
100
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xav056Author Commented:
cyberwiki:
I am getting slightly different numbers, for the rows below
17.32522796
17.97385621
25.45180723
31.39534884
32.86852590
32.95454545
36.97916667
37.84277879
39.31451613
40.92409241
41.59445407
49.30069930
50.59021922
52.03915171
53.68098160
57.50853242
59.20873124
59.49554896
60.35665295
64.09168081
70.95238095
84.94208494
92.28855721
92.28971963
92.45689655
93.47442681

I am getting
36.97916667                    52.03915171               64.09168081                 93.47442681
while excel is giving
37.1950697                         51.31468547                   63.15792385               93.47442681
the only extra thing I did was added a partition by colum2 before the order by for the ntile function, and the row number
as my original result set had 2 columns
where rows were seperated by groups of column 2

Any idea why that might be happening?
Thank you
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cyberkiwiCommented:
The reason is that Excel takes the quartiles at predetermined locations.
For your original 57-row query, the quartiles are at positions (57-1)/4 = 14 apart.  Or rather, the layout is

Ignoring 1, and adding 14 for each quartile, the positions are 15, 29, 43, 57

Using your new data with 26 elements, the quartiles should be (26-1)/4 = 6.25 apart, or positions

7.25, 13.5, 19.75, 26

There is no item at position 7.25, so instead that is calculated from (7th x 0.75 + 8th x 0.25)
Whether Excel's interpretation is correct or not is up for debate.
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xav056Author Commented:
Although its still not crystal clear on how excel is calculating the position, is there an easy way to get exact results I am getting in excel using sql
thank you
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cyberkiwiCommented:

;with tmp as (
	select c=COUNT(*) over (), rn=ROW_NUMBER() over (order by n), n
	from quartile_test)
,qs as (
	select
		q1=1+(c-1.0)/4, q1a=FLOOR(1+(c-1.0)/4), q1b=CEILING(1+(c-1.0)/4),
		q2=1+(c-1.0)/2, q2a=FLOOR(1+(c-1.0)/2), q2b=CEILING(1+(c-1.0)/2),
		q3=1+(c-1.0)*3/4, q3a=FLOOR(1+(c-1.0)*3/4), q3b=CEILING(1+(c-1.0)*3/4)
	from (select top 1 c from tmp) x)
select (1-q1+q1a)*MIN(n)+(q1-q1a)*MAX(n)
from tmp,qs where rn in (q1a,q1b) group by qs.q1,qs.q1a,qs.q1b
union all
select (1-q2+q2a)*MIN(n)+(q2-q2a)*MAX(n)
from tmp,qs where rn in (q2a,q2b) group by qs.q2,qs.q2a,qs.q2b
union all
select (1-q3+q3a)*MIN(n)+(q3-q3a)*MAX(n)
from tmp,qs where rn in (q3a,q3b) group by qs.q3,qs.q3a,qs.q3b
union all
select n
from tmp,qs where rn=c

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