delphi DayOfYear

this should be pretty straightforward - i just have a coder's block at the moment.

i guess the 2010 is not part of DayOfYear - i said i had coder' s block

so i need function to convert 249 (DOY) to 9/6 (mo/day)

Obviously you need the year, because 249 is different when it is a leap year and when not, right??

ok

why not look in the DateUtils unit next time ?

There is the incday function which should be the easiest

Result := IncDay(EncodeDate(year, 1, 1), daynum-1);

How is your line

Result := IncDay(EncodeDate(year, 1, 1), daynum-1);

different to my line

Result := EncodeDate(year,1,1)-1+dayNum;

which skips the function and uses floating point register directly.
The other content of the function is only to default to current year.

Unless there is some magic to IncDay that I am not aware of?

it is not different cyberkiwi,
i was more responding to forgetting things and having blackouts (usually monday morning)

the best to thing then is to look in those units for some unblocking ideas