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How do I Nest cases or If in CASE MS SQL

Posted on 2010-09-07
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Last Modified: 2012-05-10
I have the following condition in my query
WHERE      StartDate>=@UserDate
      AND
      CASE @Type
            WHEN 1 THEN      CASE WHEN  yearCol  =  @year THEN 1 ELSE 0 END
            WHEN 2 THEN       CASE WHEN  color<>@Color THEN 1 ELSE 0 END
            END = 1
In some case I have @Tpype=2 and @color=null
What I would like to do in the second statement (when 2 then..) check to see if @color is null where I will do something like this
CASE @color
     When null THEN CASE color<>@NewColor THEN 1 ELSE 0 END
     When not Null Then CASE color <> @Color THEN 1 ELSE 0 END
END=1
The above syntax is incorrect what's the right syntax please note that what I am doing in those cases is executing a condition based on the case
Thank you
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Comment
Question by:xav056
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9 Comments
 
LVL 39

Expert Comment

by:appari
ID: 33623952
try this

WHERE      StartDate>=@UserDate
      AND
      CASE @Type
            WHEN 1 THEN      CASE WHEN  yearCol  =  @year THEN 1 ELSE 0 END
            WHEN 2 THEN      
      CASE
           When @color is null THEN CASE color<>@NewColor THEN 1 ELSE 0 END
                When @color is not Null Then CASE color <> @Color THEN 1 ELSE 0 END
      end
END=1
0
 
LVL 58

Accepted Solution

by:
cyberkiwi earned 250 total points
ID: 33623966
Or flat without nesting

WHERE StartDate>=@UserDate
      AND
      CASE  WHEN @Type=1 AND yearCol = @year THEN 1
            WHEN @Type=1 THEN 0
            WHEN @Type=2 AND @color IS NOT NULL AND color<>@Color THEN 1
            WHEN @Type=2 AND @color IS NOT NULL THEN 0
            WHEN @Type=2 AND @color IS NULL AND color<>@NewColor THEN 1
            WHEN @Type=2 AND @color IS NULL THEN 0
      END = 1
0
 
LVL 9

Author Comment

by:xav056
ID: 33623971
incorrect syntax wiggly lines under the <> anf then
e.GDID<>@GDID (incorrect syntax bear <> and incorrect syntax near then

Thank you
0
 
LVL 39

Expert Comment

by:appari
ID: 33623982
>>incorrect syntax wiggly lines under the <> anf then
>>e.GDID<>@GDID (incorrect syntax bear <> and incorrect syntax near then
seems the error is now from a different place. post your complete query.
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LVL 9

Author Comment

by:xav056
ID: 33624000
appari
nothing before just
Select *
from VehInfo
WHERE      StartDate>=@UserDate
      AND
      CASE @Type
            WHEN 1 THEN      CASE WHEN  yearCol  =  @year THEN 1 ELSE 0 END
            WHEN 2 THEN      
      CASE
           When @color is null THEN CASE color<>@NewColor THEN 1 ELSE 0 END
                When @color is not Null Then CASE color <> @Color THEN 1 ELSE 0 END
      end
END=1
0
 
LVL 39

Assisted Solution

by:appari
appari earned 250 total points
ID: 33624007
missed when,

Select *
from VehInfo
WHERE      StartDate>=@UserDate
      AND
      CASE @Type
            WHEN 1 THEN      CASE WHEN  yearCol  =  @year THEN 1 ELSE 0 END
            WHEN 2 THEN      
      CASE
           When @color is null THEN CASE when color<>@NewColor THEN 1 ELSE 0 END
                When @color is not Null Then CASE when color <> @Color THEN 1 ELSE 0 END
      end
END=1
0
 
LVL 9

Author Closing Comment

by:xav056
ID: 33624024
Thank you both
0
 
LVL 58

Expert Comment

by:cyberkiwi
ID: 33624066
A properly nested CASE statement - 3 levels, can become really confusing

      CASE
      WHEN @Type=1 THEN
               CASE WHEN yearCol = @year THEN 1 ELSE 0 END
      WHEN @Type=2 THEN
           CASE
           WHEN @color IS NOT NULL THEN
                CASE WHEN color<>@Color THEN 1 ELSE 0 END
           ELSE -- the complement is clearly null
                CASE WHEN color<>@NewColor THEN 1 ELSE 0 END
           END
      END = 1
0
 
LVL 58

Expert Comment

by:cyberkiwi
ID: 33624076
Sorry was distracted, here's part 3 of 3.
For your case, you only want @newcolor when @color is null, you can use a better technique instead of CASE

      CASE
      WHEN @Type=1 THEN
           CASE WHEN yearCol = @year THEN 1 ELSE 0 END
      WHEN @Type=2 THEN
           CASE WHEN color<>Coalesce(@Color,@NewColor) THEN 1 ELSE 0 END
      END = 1
0

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