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How to connect to multiple database via mysqli?

Posted on 2010-09-08
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Last Modified: 2013-12-13
Hello,

I have created a class when I used to connect to the database using the __construct function.  This class also act as my selecting and executing of query.  I get this working for connecting to one database as I define the database host, username, password and db_name as a constant.  Now I want to somehow be able to pass different database name to this class, how can I do this so that this class continue to work?  For example, my constant DB_NAME is "test database".  I want to contact to another database name "test2 database".  How can I make it work?

My code for my class:

**note the upper case name is define in another file**

class QueryBuilder
{
public $host = DB_HOST;
public $db_username = DB_USERNAME;
public $db_password = DB_PASSWORD;
public $db_name = DB_NAME;

public function __construct()
{
      $this->mysqli = new mysqli($this->host,$this->db_username,$this->db_password,$this->db_name);      
}

public function __destruct()
{
      $this->mysqli->close();
}

public function select($sql)
{
      $qry = $this->mysqli->query($sql);
}

public function query($sql)
{
      $qry = $this->mysqli->query($sql);
}

}
0
Comment
Question by:bigjdve
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6 Comments
 
LVL 111

Expert Comment

by:Ray Paseur
ID: 33628324
Pass the credentials to the constructor as arguments, just like the select and query methods.
0
 
LVL 111

Accepted Solution

by:
Ray Paseur earned 2000 total points
ID: 33628376
Example...

HTH, ~Ray
<?php // RAY_temp_thing.php
error_reporting(E_ALL);

class QueryBuilder
{
    public function __construct($h, $u, $p, $n)
    {
        $this->mysqli = new mysqli($h, $u, $p, $n);
    }
}

$x = new QueryBuilder (1,2,3,4);

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0
 
LVL 3

Author Comment

by:bigjdve
ID: 33628735
Ray_Paseur - the connection is working.  However, in my select or query method, I can not execute the query.

In my select method:

$qry = $this->mysqli->query($sql);

It does seem to recognize the "$this->mysqli".  I have this code for escaping the character
($this->mysqli->real_escape_string($value)) and it does not perform the escaping.

If I echo out the statement that build that sql statement, it does not understand.

For example:

echo $sql = "select * from table where id=".$this->mysqli->real_escape_string($value);

result: "select * from table where id="";

If I remove the escape string, it will properly echo with "select * from table where id=1".

Any ideas why??
0
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LVL 111

Expert Comment

by:Ray Paseur
ID: 33629605
I did not see any escape code in the example above.  Can you please post THE ACTUAL CODE that is causing the issue?
0
 
LVL 3

Author Closing Comment

by:bigjdve
ID: 33629627
This solution does work.  There was a typo in my password.
0
 
LVL 111

Expert Comment

by:Ray Paseur
ID: 33629661
Ha!  Glad you got it working, and thanks for the points, ~Ray
0

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