Link to home
Start Free TrialLog in
Avatar of singi007
singi007

asked on

Access 2003 Query return values that have

I am trying to create a query in MS Access to display users with training dates that are going to expire within 1 week (trainings expire a year from previous training date).  I am familiar with Oracle's date function and using truncate, however I am having issues finding the equivalent in MS Access.


SELECT Employees.Last_Name, Employees.First_Name, Employees.Dept, Employees.Last_Training_Date, Employees.Notes
FROM Employees
WHERE (([Last_Training_Date]< "yyyy", -1, Date()));
Avatar of NEVAEHSIN
NEVAEHSIN

You can try...

[Last_Training_Date]<=DateAdd("yyyy", -1, Date)
Avatar of singi007

ASKER

It says "Data type mismatch in criteria expression" and I think that would just get me 1 year past, I need it to give me the users that are within 1 week of a year past due.
First off - is [Last_Training_Date] Date/Time format?

Next try....
 where DateAdd("yyyy",1,Last_Training_date)>DateAdd("d",-7,Date());
Avatar of Patrick Matthews
Catches those who are both overdue, and who have a week left:


SELECT Employees.Last_Name, Employees.First_Name, Employees.Dept, Employees.Last_Training_Date, Employees.Notes
FROM Employees
WHERE DateAdd("yyyy", -1, DateAdd("d", -7, Date())) <= [Last_Training_Date])

Open in new window

Yes, Last_Training_Date is a Date/Time format. The syntax

WHERE DateAdd("yyyy", -1, DateAdd("d", -7, Date())) >= [Last_Training_Date]

gives me those that are both overdue and who have a week left, but I want to differentiate between the two. Is it possible to break it into 2 queries? or some other method of displaying the 2 different groups?
Give this a try:
SELECT Employees.Last_Name, Employees.First_Name, Employees.Dept, Employees.Last_Training_Date, Employees.Notes,
    IIf(DateAdd("yyyy", 1, [Last_Training_Date]) > Date(), "Overdue", "Expiring Soon") AS Status
FROM Employees
WHERE DateAdd("yyyy", -1, DateAdd("d", -7, Date())) <= [Last_Training_Date])

Open in new window

Ok, I think from your solution I figured out how to get and differentiate the overdue employees and the overdue in the next 7 days employees. Is there anyway to use this IIf function to differentiate between 3 sets, for example the overdue employees, employees 7 days from being overdue and 6 weeks from being overdue? or does the IIf function only allow 2?
SELECT Employees.Last_Name, Employees.First_Name, Employees.DEPT, Employees.Last_Training_Date, Employees.Notes,
IIf(DateAdd("d", 365 , [Last_Training_Date]) < Date(), "Overdue", "Expiring within 7 Days") AS Status
FROM Employees
WHERE ( DateAdd("d", -358, Date())) >= [Last_Training_Date]
order by Last_Training_Date;

Open in new window

ASKER CERTIFIED SOLUTION
Avatar of Patrick Matthews
Patrick Matthews
Flag of United States of America image

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Thank you! This is exactly what I was trying to figure out. I thought it would be easy to figure out the rest once I had the first part, but then realized it wasn't as simple as I had hoped.
singi007,Glad to help!  If you have not already done so, I would really appreciate it if you could please return to my articlehttps://www.experts-exchange.com/Microsoft/Development/MS_Access/A_3556-Using-the-Switch-Function-in-Microsoft-Access.htmland click 'Yes' for the 'Was this helpful?' voting.matthewspatrick