MySQL Problem

In a solution provided in a previous question I was given this:

$rd = $_REQUEST['start_date'];
$sql = "SELECT * FROM `listings` WHERE `date` >= date_add(str_to_date('$rd', '%d/%M/%Y'), interval -3 day) and `date` < date_add(str_to_date('$rd', '%d/%M/%Y'), interval 4 day) ";

I need to know if this would work:

$rd = $_REQUEST['start_date'];
$sql = "SELECT * FROM `listings` WHERE str_to_date(`date`, '%d/%M/%Y') >= date_add(str_to_date('$rd', '%d/%M/%Y'), interval -3 day) and str_to_date(`date`, '%d/%M/%Y') < date_add(str_to_date('$rd', '%d/%M/%Y'), interval 4 day) ";

MySQL ServerPHPWeb Development

Last Comment

cyberkiwi

8/22/2022 - Mon

ASKER CERTIFIED SOLUTION

cyberkiwi

9/11/2010

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cyberkiwi

9/11/2010

Using any function on the `date` column also causes an index on that column to be unusable. Consider making a date range that will cover the date+time involved.
If `date` contains time data and you want to include the 7th day, then try this

$rd = $_REQUEST['start_date'];
$sql = "SELECT * FROM `listings` WHERE `date` >= date_add(str_to_date('$rd', '%d/%M/%Y'), interval -3 day) and `date` < date_add(str_to_date('$rd', '%d/%M/%Y'), interval 5 day) ";

< ".. interval 5 days "

will include any hour on the day "$rd +4 days"

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