asked on

Binary to Text, Text to Binary - Part II

I would like to refine some work i had help on

see: https://www.experts-exchange.com/questions/26470056/Binary-to-Ascii-Text-and-Visa-Versa.html

I have two memos and two convert buttons

Convert Binary to text button (Converts Binary in memOne and displays text in memTwo)

Convert Text to Binary button (Converts text in memOne and displays binary in memTwo)

see code below (by EE expert - epasquier)

I would like to have one Tmemo, and one button (convert)

Is this possible

When the convert button is clicked, it checks the Tmemo and determines if the memo is all zeros and ones and then converts to words (text), else it checks to see that its just words (text) and then converts to binary

thanks

procedure TfrmConversionsBinary.btnConvertBinarytoTextClick(Sender: TObject);
begin
 memTwo.Lines.Text:= BinToString(memOne.Lines.Text, True);
end;

procedure TfrmConversionsBinary.btnConvertTexttoBinaryClick(Sender: TObject);
begin
 memTwo.Lines.Text:= StringToBin(memOne.Lines.Text);
end;



//******************** BINARY *************************

function BinToInt(Bin:String;ThrowException:Boolean=False):Cardinal;
Var
 i,L:integer;
begin
 Result:=0;
 i:=1;
 L:=Length(Bin);
 While i<=L do
  begin
   Result:=Result SHL 1;
   if Bin[i]='1'
    Then Inc(Result)
    Else if ThrowException And (Bin[i]<>'0')
     Then Raise Exception.Create('Invalid binary digit in ['+Bin+']');
   Inc(i);
  end;
end;

function IntToBin(C:Cardinal;Digits:Byte=8):String;
Var
 N:Byte;
Const
 Bits='01';
begin
 Result:='';
 N:=0;
 While (C>0) Or (N=0) Or ((N Mod Digits)>0) do
  begin
   Result:=Bits[(C And 1)+1]+Result;
   C:=C SHR 1;
   Inc(N);
  end;
end;

function StringToBin(S:String):String;
Var
 i:integer;
begin
 Result:='';
 for i:=1 to Length(S) do Result:=Result+IntToBin(Ord(S[i]));
end;

function BinToString(S:String;ThrowException:Boolean=False):String;
Var
 N:Integer;
begin
 Result:='';
 N:=Length(S);
 if ThrowException And ((N Mod 8)>0) Then Raise Exception.Create('Number of binary digits must be a multiple of 8');
 While N>0 do
  begin
   Result:=Result+Char(BinToInt(Copy(S,1,8),ThrowException));
   S:=Copy(S,9,N);
   N:=N-8;
  end;
end;


//******************** END BINARY *************************

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ASKER CERTIFIED SOLUTION

Emmanuel PASQUIER

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NevTon

Hi,

Better way is to examine the memo in a loop (I hope that this text is not very large) for having something else than zeros and ones.
This always work.
If in this memo is only 0 and 1 convert to text else this is text, convert it to bins.

function ToBins(AText: String): String;
var
  i: Integer;

  function dectobin(dec: Byte): String;
  var
    j: Byte;
  begin
    Result:='';
    for j:=0 to 7 do begin
      if (dec shr (7 - j) and 1) = 1 then
        Result:=Result + '1'
      else
        Result:=Result + '0';
    end;
  end;

begin
  Result:='';
  for i:=1 to Length(AText) do begin
    Result:=Result + dectobin(ord(AText[i]));
  end;
end;

function ToText(ABins: String): String;
var
  i: Integer;

  function bintodec(bin: String): Byte;
  var
    j: Byte;
  begin
    Result:=0;
    if Length(bin) < 8 then
      Exit;
    for j:=1 to 8 do begin
      if bin[j] = '1' then
        Result:=Result + (1 shl (8 - j));
    end;
  end;

begin
  Result:='';
  for i:=1 to (Length(ABins) div 8) do begin
    Result:=Result + chr(bintodec(Copy(ABins, 1, 8)));
    Delete(ABins, 1, 8);
  end;
end;

function IsBins(AText: String): Boolean;
var
  i: Integer;
begin
  Result:=True;
  for i:=1 to Length(AText) do begin
    if not (AText[i] in ['0', '1']) then
      Result:=False;
  end;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
 if IsBins(Memo1.Lines.Text) then
   Memo1.Lines.Text:=ToText(Memo1.Lines.Text)
 else
   Memo1.Lines.Text:=ToBins(Memo1.Lines.Text);
end;

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Emmanuel PASQUIER

Hi Looking_4_Answers !

Have you tried the solution I provided ?