Solved

Binary to Text, Text to Binary - Part II

Posted on 2010-09-14
3
693 Views
Last Modified: 2012-08-14
I would like to refine some work i had help on

see: http://www.experts-exchange.com/Programming/Languages/Pascal/Delphi/Q_26470056.html

I have two memos and two convert buttons

Convert Binary to text button (Converts Binary in memOne and displays text in memTwo)

Convert Text to Binary button (Converts text in memOne and displays binary in memTwo)

see code below (by EE expert - epasquier)

I would like to have one Tmemo, and one button (convert)

Is this possible

When the convert button is clicked, it checks the Tmemo and determines if the memo is all zeros and ones and then converts to words (text), else it checks to see that its just words (text) and then converts to binary


thanks
procedure TfrmConversionsBinary.btnConvertBinarytoTextClick(Sender: TObject);

begin

 memTwo.Lines.Text:= BinToString(memOne.Lines.Text, True);

end;



procedure TfrmConversionsBinary.btnConvertTexttoBinaryClick(Sender: TObject);

begin

 memTwo.Lines.Text:= StringToBin(memOne.Lines.Text);

end;







//******************** BINARY *************************



function BinToInt(Bin:String;ThrowException:Boolean=False):Cardinal;

Var

 i,L:integer;

begin

 Result:=0;

 i:=1;

 L:=Length(Bin);

 While i<=L do

  begin

   Result:=Result SHL 1;

   if Bin[i]='1'

    Then Inc(Result)

    Else if ThrowException And (Bin[i]<>'0')

     Then Raise Exception.Create('Invalid binary digit in ['+Bin+']');

   Inc(i);

  end;

end;



function IntToBin(C:Cardinal;Digits:Byte=8):String;

Var

 N:Byte;

Const

 Bits='01';

begin

 Result:='';

 N:=0;

 While (C>0) Or (N=0) Or ((N Mod Digits)>0) do

  begin

   Result:=Bits[(C And 1)+1]+Result;

   C:=C SHR 1;

   Inc(N);

  end;

end;



function StringToBin(S:String):String;

Var

 i:integer;

begin

 Result:='';

 for i:=1 to Length(S) do Result:=Result+IntToBin(Ord(S[i]));

end;



function BinToString(S:String;ThrowException:Boolean=False):String;

Var

 N:Integer;

begin

 Result:='';

 N:=Length(S);

 if ThrowException And ((N Mod 8)>0) Then Raise Exception.Create('Number of binary digits must be a multiple of 8');

 While N>0 do

  begin

   Result:=Result+Char(BinToInt(Copy(S,1,8),ThrowException));

   S:=Copy(S,9,N);

   N:=N-8;

  end;

end;





//******************** END BINARY *************************

Open in new window

0
Comment
Question by:Looking_4_Answers
  • 2
3 Comments
 
LVL 25

Accepted Solution

by:
epasquier earned 500 total points
Comment Utility
Try to convert BinToString with ThrowException = True.
If the source is not compatible with Binary representation of some text, then it will raise an exception.
Trap that exception, and in this case you convert the string to binary, which always succeed.
procedure TfrmConversionsBinary.btnConvertBinarytoTextClick(Sender: TObject);

begin

 try

  memOne.Lines.Text:= BinToString(memOne.Lines.Text, True);

 except

  memOne.Lines.Text:= StringToBin(memOne.Lines.Text);

 end; 

end;

Open in new window

0
 
LVL 3

Expert Comment

by:NevTon
Comment Utility
Hi,

Better way is to examine the memo in a loop (I hope that this text is not very large) for having something else than zeros and ones.
This always work.
If in this memo is only 0 and 1 convert to text else this is text, convert it to bins.

function ToBins(AText: String): String;
var
  i: Integer;

  function dectobin(dec: Byte): String;
  var
    j: Byte;
  begin
    Result:='';
    for j:=0 to 7 do begin
      if (dec shr (7 - j) and 1) = 1 then
        Result:=Result + '1'
      else
        Result:=Result + '0';
    end;
  end;

begin
  Result:='';
  for i:=1 to Length(AText) do begin
    Result:=Result + dectobin(ord(AText[i]));
  end;
end;

function ToText(ABins: String): String;
var
  i: Integer;

  function bintodec(bin: String): Byte;
  var
    j: Byte;
  begin
    Result:=0;
    if Length(bin) < 8 then
      Exit;
    for j:=1 to 8 do begin
      if bin[j] = '1' then
        Result:=Result + (1 shl (8 - j));
    end;
  end;

begin
  Result:='';
  for i:=1 to (Length(ABins) div 8) do begin
    Result:=Result + chr(bintodec(Copy(ABins, 1, 8)));
    Delete(ABins, 1, 8);
  end;
end;

function IsBins(AText: String): Boolean;
var
  i: Integer;
begin
  Result:=True;
  for i:=1 to Length(AText) do begin
    if not (AText[i] in ['0', '1']) then
      Result:=False;
  end;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
 if IsBins(Memo1.Lines.Text) then
   Memo1.Lines.Text:=ToText(Memo1.Lines.Text)
 else
   Memo1.Lines.Text:=ToBins(Memo1.Lines.Text);
end;

Open in new window

0
 
LVL 25

Expert Comment

by:epasquier
Comment Utility
Hi Looking_4_Answers !

Have you tried the solution I provided ?
0

Featured Post

Do You Know the 4 Main Threat Actor Types?

Do you know the main threat actor types? Most attackers fall into one of four categories, each with their own favored tactics, techniques, and procedures.

Join & Write a Comment

Creating an auto free TStringList The TStringList is a basic and frequently used object in Delphi. On many occasions, you may want to create a temporary list, process some items in the list and be done with the list. In such cases, you have to…
Introduction Raise your hands if you were as upset with FireMonkey as I was when I discovered that there was no TListview.  I use TListView in almost all of my applications I've written, and I was not going to compromise by resorting to TStringGrid…
It is a freely distributed piece of software for such tasks as photo retouching, image composition and image authoring. It works on many operating systems, in many languages.
This tutorial demonstrates a quick way of adding group price to multiple Magento products.

772 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

10 Experts available now in Live!

Get 1:1 Help Now