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need some good Hex to string / String to Hex functions

Posted on 2010-09-15
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Last Modified: 2012-05-10
I have a form with two memos and two butons (hex to text & text to hex)

I need two functions which can take hex and convert to text and visa versa

bonus is you add exceptions (error code checking)

thanks
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Question by:Looking_4_Answers
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5 Comments
 

Author Comment

by:Looking_4_Answers
ID: 33682797
example, would be:

http://www.dolcevie.com/js/converter.html


without the colons  (maybe spaces instead)
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LVL 25

Expert Comment

by:epasquier
ID: 33682945
Here is already the one that I talked you about. It can manage a lot of formatting options. You might want to simplify this : drop the C definition and Indentation functionalities - they are useful with C code generation.

It is also based on a pointer on Char and a number of characters. This is more versatile as it can be used to convert about anything, but you might prefer a simple String parameter for input.

Other parameters : Col & Hewawidth controls the grouping of hexa bytes in columns and lines.
HexaWidth will be the Nb of bytes that are rendered together without spaces between. Ex : 4 will show display the hexa values for 32 bits.
Col is the number of bytes before a line ret is added. Col must be a multiple of HexaWidth, except if Col =0 (no line ret)

Ex : Col = 6, HexaWidth =2 will return something like for a buffer of 9 bytes:
A0B6 F43D 76A3
98D6 3F

The same with Col=0 and HexaWidth=1 (the simple one byte separated hexa formatting)
A0 B6 F4 3D 76 A3 98 D6 3F

Function BufToHexStr(N:Cardinal;Buf:pCharTab;Col:Byte=0;HexaWidth:Byte=0;CDef:Boolean=False;Indent:Byte=0):String;

Var

 i:Integer;

 Hdr,Ftr,NewL,IdtStr:String;

begin

 if Buf=nil Then Exit;

 IdtStr:=DupeString(' ',Indent);

 NewL:=CRLF+IdtStr;

 if CDef Then

  begin

   Result:='{ ';

   Hdr:='0x';

   Ftr:=' ,';

  end Else

  begin

   Result:='';

   Ftr:=' ';

   Hdr:='';

  end;

 if HexaWidth>0 Then while (Col MOD HexaWidth)>0 do Dec(HexaWidth);

 For i:=0 to N-1 do

  begin

   if (i>0) And (HexaWidth>0) And ((i Mod HexaWidth)=0) Then Result:=Result+Ftr;

   if (Col>0) And (i>0) And ((i Mod Col)=0) Then

    begin

     Result:=Result+NewL;

     if CDef Then Result:=Result+'  ';

    end;

   Result:=Result+Hdr+HexaChar(Buf^[i]);

  end;

 if CDef Then Result:=Result+NewL+'}';

end;

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Expert Comment

by:epasquier
ID: 33683200
And this is the reverse, it can ignore any characters that is not hexa digit and consider those as separators
Note that the hexa digits don't have to be paired if separated, for ex.
9B 06 3F = 9B 6 3F = 9B06,3F

I added the same exception mechanism for you as in the Bin convertion, as I'm sure your next question is how try this one conversion and if it fails call the String To Hexa ;o)

I also simplified BufToHexStr and removed any reference to other functions I have
Function HexaStrToBuf(Src:ANSIString;ThrowException:Boolean=False):ANSIString;

begin

 For i:=1 to Length(Src) do

  if Not (Src[i] IN ['0'..'9','A'..'F']) Then 

   begin

    if ThrowException And Not (Src[i] In [' ',#13,#10]) Then Raise Exception.Create('Invalid Hexa character');

    Text[i]:=' ';

   end;

 P:=1;

 Result:='';

 While P<=Length(Src) do if Src[P]=' ' Then Inc(P) Else

  begin

   Result:=Result+Char(StrToInt('$'+Trim(Copy(Src,P,2))));

   Inc(P,2);

  end;

end;



Function BufToHexStr(Src:ANSIString;Col:Byte=0;HexaWidth:Byte=0):ANSIString;

Var

 i:Integer;

begin

 Result:='';

 if HexaWidth>0 Then while (Col MOD HexaWidth)>0 do Dec(HexaWidth);

 For i:=0 to Length(Src)-1 do

  begin

   if (i>0) And (HexaWidth>0) And ((i Mod HexaWidth)=0) Then Result:=Result+' ';

   if (Col>0) And (i>0) And ((i Mod Col)=0) 

    Then Result:=Result+#13#10;

   Result:=Result+Format('%2.2x',[Byte(Src[i+1])]);

  end;

end;

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Author Comment

by:Looking_4_Answers
ID: 33685012
kool, i will test it - thanks
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LVL 25

Accepted Solution

by:
epasquier earned 500 total points
ID: 33763333
are you done testing ? do you need something else ?
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