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Sizeof on Structure With Arrays

Hey again,

Lotsa questions this week.  Can someone go into some detail and explain what happens here?

#include <iostream>
using namespace std;

struct SomeFakeData
{
    int intArray[10];
    char charArray[10];
};

struct Test
{
    SomeFakeData sfd[20];
    int xx;
    const char* yy;
};

int main()
{
    Test test;
    test.xx = 99;
    test.yy = "str99str";
    test.sfd[1].intArray[4] = 32;
    test.sfd[1].charArray[3] = 'H';

    cout<<sizeof(Test)<<endl;
    cout<<sizeof(test)<<endl;
}


Okay, so using this crappy example, both sizeof statements return the same result, even though the c-string held within the strucutre, test, has been given a value which should take more bytes than it previously did.  I get that this is because sizeof() probably took the size of the pointer rather than the sizeof what it pointed to.

My question is:

If I'm calculating the size of object test, can I assume that the size of the arrays is already incorporated to what gets output when I do sizeof(Test)?  Can someone give me a line of code that calculates the complete size of everything needed to hold the complete instance "test"?

Thanks in advance!

-w00te
0
w00te
Asked:
w00te
  • 3
1 Solution
 
Infinity08Commented:
The values you use do not impact the size. sizeof is a compile time construct. It returns the size of the entire struct, and that size does not change while the program runs.
0
 
Infinity08Commented:
The size of the struct will be :

        20 * sizeof(SomeFakeData) + sizeof(int) + sizeof(char*) + padding

and sizeof(SomeFakeData) will similarly be :

        10 * sizeof(int) + 10 * sizeof(char) + padding

Note that the padding is implementation dependent. There might or might not be padding between the struct fields and/or at the end of the struct.
0
 
Infinity08Commented:
>> Can someone give me a line of code that calculates the complete size of everything needed to hold the complete instance "test"?

I'm not sure what you mean by this, but sizeof gives you the complete size of the struct, including arrays.

Note though that for the const char* pointer, sizeof only includes the size of the pointer itself - not the data it points to !
0

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