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MSSQL Distinct, help

Posted on 2010-09-16
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Medium Priority
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Last Modified: 2012-05-10
Hey all,

I have an issue I have 2 tables with about 20,000 rows in. It contains name, email pins etc. Below see my SQL to retrieve all of the data.

What I need is a way of DISTINCTLY selecting the results but take the one with the highest X_ID.

SELECT x_id, name, email, primarypin
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id

This will return for example.

X_ID, name, email, primarypin
11, SChurch, SChurch@dsa.com, 115545544
12, SChurch, Schurch@dsa.com, 151516165

I would like to select the result with ID 12.
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Question by:KazooSoft
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7 Comments
 
LVL 143

Expert Comment

by:Guy Hengel [angelIII / a3]
ID: 33690132
you might want to read this article:http://www.experts-exchange.com/A_3203.html
0
 
LVL 5

Expert Comment

by:Priya Perumpilavil
ID: 33690218
try this
SELECT max(x_id), max(name), max(email), max(primarypin)
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id
group by name
0
 
LVL 23

Accepted Solution

by:
Rajkumar Gs earned 2000 total points
ID: 33690224
Try this
Raj
SELECT x_id, name, email, primarypin FROM
(
	SELECT x_id, name, email, primarypin
		, row_number() over (partition by [name], email order by X_ID desc) rowno 
	FROM cas_user_ext, cat_validation
	WHERE cas_user_ext.x_id = cat_validation.id
) A
WHERE A.ROWNO = 1

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0
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LVL 23

Expert Comment

by:Racim BOUDJAKDJI
ID: 33690276
Below...

HTH
SELECT distinct name, email, primarypin, max(x_id) as highest_x_id
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id
group by name, email, primarypin

Open in new window

0
 
LVL 23

Expert Comment

by:Racim BOUDJAKDJI
ID: 33690303
Sorry I misread the question..pls try...
select distinct
A.name, A.email, A.primarypin, A.x_id
from
(
select name, email, primarypin, x_id
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id
) A
inner join
(
SELECT distinct name, email, primarypin, max(x_id) as highest_x_id
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id
group by name, email, primarypin
) B
on A.x_id = B.highest_x_id

Open in new window

0
 
LVL 5

Expert Comment

by:Priya Perumpilavil
ID: 33690395
try this
SELECT max(x_id), name, max(email), max(primarypin)
FROM cas_user_ext, cat_validation
WHERE cas_user_ext.x_id = cat_validation.id
group by name

0
 
LVL 8

Expert Comment

by:Gururaj Badam
ID: 33690445
This is what you're looking for. I'm doing a self join to get the max record and then return the pertaining columns

SELECT a.x_id, a.name, a.email, a.primarypin
FROM cas_user_ext a, cas_user_ext b, cat_validation
WHERE b.x_id = cat_validation.id and max(b.x_id) = a.x_id
0

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