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PHP: Remove items from an array if foobar empty

Posted on 2010-09-16
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Last Modified: 2012-05-10
If foobar is empty then I want to remove the entire item from my array.
<?php

$a = array();
$a[]=array('id'=>1,'Name'=>'Abc','foobar'=>null);
$a[]=array('id'=>2,'Name'=>'Jkl','foobar'=>'Hello');
$a[]=array('id'=>3,'Name'=>'Qrs','foobar'=>'Test');
$a[]=array('id'=>4,'Name'=>'Xyz','foobar'=>'');

echo '<pre>';
print_r($a);
echo '</pre>';

?>

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Question by:hankknight
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2 Comments
 
LVL 10

Expert Comment

by:Tyler Laczko
ID: 33693603
<?php

$a = array();
$a[]=array('id'=>1,'Name'=>'Abc','foobar'=>null);
$a[]=array('id'=>2,'Name'=>'Jkl','foobar'=>'Hello');
$a[]=array('id'=>3,'Name'=>'Qrs','foobar'=>'Test');
$a[]=array('id'=>4,'Name'=>'Xyz','foobar'=>'');

for($i=0; $i<array_len($a); $i++)
{
  if($a[$i]['foobar'] == '')
  {
    $a[$i] = NULL;
  }
}
echo '<pre>';
print_r($a);
echo '</pre>';

?>
0
 
LVL 10

Accepted Solution

by:
Tyler Laczko earned 500 total points
ID: 33693935
sorry. this is MUCH BETTER!!!!


<?php

$a = array();
$a[]=array('id'=>1,'Name'=>'Abc','foobar'=>null);
$a[]=array('id'=>2,'Name'=>'Jkl','foobar'=>'Hello');
$a[]=array('id'=>3,'Name'=>'Qrs','foobar'=>'Test');
$a[]=array('id'=>4,'Name'=>'Xyz','foobar'=>'');

foreach($a as $a1)
      if($a1['foobar'] != '' && $a1['foobar'] != NULL)
            $new_array[] = $a1;
      
echo '<pre>';
print_r($new_array);
echo '</pre>';


?>
<?php

$a = array();
$a[]=array('id'=>1,'Name'=>'Abc','foobar'=>null);
$a[]=array('id'=>2,'Name'=>'Jkl','foobar'=>'Hello');
$a[]=array('id'=>3,'Name'=>'Qrs','foobar'=>'Test');
$a[]=array('id'=>4,'Name'=>'Xyz','foobar'=>'');

foreach($a as $a1)
	if($a1['foobar'] != '' && $a1['foobar'] != NULL)
		$new_array[] = $a1;
	
echo '<pre>';
print_r($new_array);
echo '</pre>';


?>

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0

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