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MS SQL 2005 and @XML.exist

Posted on 2010-09-17
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Last Modified: 2012-05-10
I'm trying to store a list of data in XML variable and after I need to make a test to see if a string exists.


In my example the string I'm looking for is "Test4", but not exists in the XML.

Why when I used the @xml.exist('sql:variable("@xPath")')  the results is wrong?

declare @xml xml
set @xml =
'<?xml version="1.0" encoding="utf-8"?>
<attributes>
	<attribute  txt="test1" notes="blablaablalb"/>
	<attribute  txt="test2" notes="blablaablalb"/>
	<attribute  txt="test3" notes="blablaablalb"/>
</attributes>'

select 
	@xml.exist('/attributes/attribute[@txt = "test4"]') 

-- return 0

declare @xPath varchar(10)

set @xPath = '/attributes/attribute[@txt = "test4"]'

select 
	@xml.exist('sql:variable("@xPath")') 

-- return 1

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Can you please help to understand what I'm doing wrong or how can I used @xml.exist whit dynamics SQL?


 
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Question by:Cboudroz
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3 Comments
 
LVL 60

Expert Comment

by:Kevin Cross
ID: 33705514
Cboudroz,

This doesn't fix the ultimate issue, but your varchar(10) isn't big enough for the XPath, so fix that to varchar(50) or something of that size.  Then you may be able to use dynamic SQL like this.
declare @xPath nvarchar(50), @sql nvarchar(200)

set @xPath = N'/attributes/attribute[@txt = "test4"]'
set @sql = N'select @xmlFrag.exist('''+ @xPath +''')'

exec sp_executeSQL @sql, N'@xmlFrag xml', @xmlFrag = @xml; 

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LVL 60

Accepted Solution

by:
Kevin Cross earned 2000 total points
ID: 33705534
And this may be what you are really after and why varchar was originally only set to 10.
declare @xml xml
set @xml =
'<?xml version="1.0" encoding="utf-8"?>
<attributes>
	<attribute  txt="test1" notes="blablaablalb"/>
	<attribute  txt="test2" notes="blablaablalb"/>
	<attribute  txt="test3" notes="blablaablalb"/>
</attributes>';
declare @txt varchar(10)
set @txt = 'test4';
select @txt
     , @xml.exist('/attributes/attribute[@txt = sql:variable("@txt")]')

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0
 
LVL 7

Author Comment

by:Cboudroz
ID: 33716194
mwvisa1:

sorry for varchar(10) that wasn't the original code.  The problems was that I didn't correctly used the sql:variable function.  

Thanks for your help.



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