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Extract initials from string - oracle syntax
Posted on 2010-09-20
Hello
Have a string field which may contain one or more names seperated by a comma. I need to return just the Initials.
eg
Field1 Field2(Initials)
Fred Bloggs, Dave Smith, Eileen Bab FB, DS, EB
John Sayer JS
etc etc
Have a string field which may contain one or more names seperated by a comma. I need to return just the Initials.
eg
Field1 Field2(Initials)
Fred Bloggs, Dave Smith, Eileen Bab FB, DS, EB
John Sayer JS
etc etc
[X]
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11 Comments
you mean field2 is the output you wanted ? do you need it as single sql query or pl/sql code block is also ok for you ?
try this :
create or replace function f1(var varchar2) return varchar2
is
rr varchar2(100) :=null;
begin
rr:= substr(var,1,1);
for x in 1..length(var) loop
if ( substr(var,x,1) = ' ') then
rr := rr || substr(var,x+1,1);
elsif ( substr(var,x,1) = ',') then
rr := rr || substr(var,x,1);
end if;
end loop;
return rr;
end;
/
select name1, f1(name1) from test1;
This works for me as you wanted.
But this can also be done with single sql with or without regular expressions.
Thanks
create or replace function f1(var varchar2) return varchar2
is
rr varchar2(100) :=null;
begin
rr:= substr(var,1,1);
for x in 1..length(var) loop
if ( substr(var,x,1) = ' ') then
rr := rr || substr(var,x+1,1);
elsif ( substr(var,x,1) = ',') then
rr := rr || substr(var,x,1);
end if;
end loop;
return rr;
end;
/
select name1, f1(name1) from test1;
This works for me as you wanted.
But this can also be done with single sql with or without regular expressions.
Thanks
The regex looks interesting- what if in the string we also have something like ....
Field 1 Required Output
Fred Bloggs, Dave Smith (Instructor), Eileen Bab FB, DS, EB
Phil Smith and Alan Vine, John Brown PS , AV, JB
So, I would like to leave out "and" and anything in brackets.
Regards
Field 1 Required Output
Fred Bloggs, Dave Smith (Instructor), Eileen Bab FB, DS, EB
Phil Smith and Alan Vine, John Brown PS , AV, JB
So, I would like to leave out "and" and anything in brackets.
Regards
Active today
you'll have to nest replacements
REGEXP_REPLACE(
REGEXP_REPLACE(REPLACE(fie
'([A-Z])[a-z ]*',
'\1'
)
REGEXP_REPLACE(
REGEXP_REPLACE(REPLACE(fie
'([A-Z])[a-z ]*',
'\1'
)
This looks good - one small problem is that if I get more than one set of brackets it leaves out
other required data - eg
Fred Bloggs, Dave Smith (Instructor), Eileen Bab (Head of Dept) it returns FB, DS.
Any good sites re regex and oracle?
other required data - eg
Fred Bloggs, Dave Smith (Instructor), Eileen Bab (Head of Dept) it returns FB, DS.
Any good sites re regex and oracle?
Active today
oops try this instead
REGEXP_REPLACE(
REGEXP_REPLACE(REPLACE(fie
'([A-Z])[a-z ]*',
'\1'
)
I use Appendix C in the SQL Reference
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/ap_posix.htm#i691974
in 11g the SQL Reference moves the Regular Expressions to Appendix D
REGEXP_REPLACE(
REGEXP_REPLACE(REPLACE(fie
'([A-Z])[a-z ]*',
'\1'
)
I use Appendix C in the SQL Reference
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/ap_posix.htm#i691974
in 11g the SQL Reference moves the Regular Expressions to Appendix D
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