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Right, is it possible to return a collection/list of the many side, i.e. for each item in SalesList have a nested List&lt;CashReceived&gt;?
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Right, is it possible to return a collection/list of the many side, i.e. for each item in SalesList have a nested List<CashReceived>?

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Thanks, that did the trick.
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Hi Silas2;<br />
<br />
You can actually close the question yourself, see help link <a href="https://www.experts-exchange.com/help.jsp#hs=29&hi=407" rel="ugc">https://www.experts-exchange.com/help.jsp#hs=29&hi=407</a>&nbsp;, Select the option &quot;Accept multiple solutions&quot;.<br />
<br />
Have a great day.<br />
Fernando
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Hi Silas2;

You can actually close the question yourself, see help link https://www.experts-exchange.com/help.jsp#hs=29&hi=407 [https://www.experts-exchange.com/help.jsp#hs=29&hi=407] , Select the option "Accept multiple solutions".

Have a great day.
Fernando

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I have two lists List&lt;Sales&gt; and List&lt;CashReceived&gt;, the List&lt;CashReceived&gt; has zero-many records for every item in &lt;Sales&gt; (its internet sales, not all payments go thru, sometimes there are multiple attempts hence zero-many). I want a Select which will bring back all the Sales and all of their related CashReceived (or maybe zero ) grouped so I can analyse each group. <br />
Is SelectMany right? I can't see how to make the join outer.
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I have two lists List<Sales> and List<CashReceived>, the List<CashReceived> has zero-many records for every item in <Sales> (its internet sales, not all payments go thru, sometimes there are multiple attempts hence zero-many). I want a Select which will bring back all the Sales and all of their related CashReceived (or maybe zero ) grouped so I can analyse each group. 
Is SelectMany right? I can't see how to make the join outer.

SelectMany - Simple Linq Question

The .NET Framework is not specific to any one programming language; rather, it includes a library of functions that allows developers to rapidly build applications. Several supported languages include C#, VB.NET, C++ or ASP.NET.