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Get the sub-domain name and verify configuration

Posted on 2010-09-22

3 solutions

Medium Priority

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Last Modified: 2012-06-27

I E's, I want to get the name of sub-domain, and at the same time verify if the sub-domain is well written.
The sub-domains just can contain 2 alpha characters, like pt, es, en, it etc.
In practice if I have this domains:
http://pt/domain.com/ or http://www.pt/domain.com/
http://es/domain.com/index.php or http://www.es/domain.com/index.php
http://en/domain.com/index.php?variables or http://www.en/domain.com/index.php?variables

The output should be pt, es or en, and the configuration of 'sub-domain' was correct.

Note: the only thing I want to know it was the configuration of sub-domain, not the entirely URL.

So, How I get sub-domain acronym and how I see if sub-domain have 2 alpha characters?

Regards, JC

Comment

Question by:Pedro Chagas

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11 Comments

LVL 4

Expert Comment

by:trencH87

ID: 337379662010-09-22

Im guessing you mean http://pt.domain.com or http://www.pt.domain.com and not pt/domain.com and so on. Try this code:

$url = "http://pt.domain.com";

$pieces = explode(".",$url);
$check = (substr($pieces[0],0,4) == "http") ? substr($pieces[0],7) : substr($pieces[0],0);
$subdomain = ($check == "www") ? $check.".".$pieces[1] : $check;
if (strstr($subdomain,".")) {
	$sub = substr($subdomain,4);
	if (strlen($sub) >= 2) {
		echo $subdomain." : Success!";
	} else {
		echo $subdomain." : Failed!";
	}
} else {
	if (strlen($subdomain) >= 2) {
		echo $subdomain." : Success!";
	} else {
		echo $subdomain." : Failed!";
	}
}

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LVL 4

Expert Comment

by:trencH87

ID: 337379932010-09-22

If you ONLY want to allow 2 - TWO - letters in subdomain, change >= to == in the IF statement.

LVL 3

Author Comment

by:Pedro Chagas

ID: 337392732010-09-22

Hi @trencH87, you try your solution before you post them?
Don't work well, with >= or ==, don't work any way.

The first failure was the kind of characters, like I tell before, the characters just can be alpha, so don't accept numeric characters.

Another failure was with or without www., if I write http://pt.domain.com the output is pt: success! but if I write http://www.pt.domain.com the output is www.pt: success, when the correct is just pt: success!

Note: I change the lines >= for == for made the tests.

Regards, JC

LVL 4

Accepted Solution

by:trencH87

trencH87 earned 700 total points

ID: 337410692010-09-22

Then try this:

$url = "http://pt.domain.com";

$pieces = explode(".",$url);
$check = (substr($pieces[0],0,4) == "http") ? substr($pieces[0],7) : substr($pieces[0],0);
$subdomain = ($check == "www") ? $check.".".$pieces[1] : $check;
if (strstr($subdomain,".")) {
	$sub = substr($subdomain,4);
	if (strlen($sub) == 2 && ctype_alpha($sub)) {
		echo $sub." : Success!";
	} else {
		echo $sub." : Failed!";
	}
} else {
	if (strlen($subdomain) == 2 && ctype_alpha($subdomain)) {
		echo $subdomain." : Success!";
	} else {
		echo $subdomain." : Failed!";
	}
}

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LVL 31

Expert Comment

by:Marco Gasi

ID: 337411602010-09-22

You can try with preg_match using this regex:
$url = one of url you posted above
preg_match("/(?<=http:\/\/)(\w\w)(?=\/)|(?<=http:\/\/www\.)/" $url, $mathces);
echo $matches[0];

Cheers

LVL 3

Author Comment

by:Pedro Chagas

ID: 337468032010-09-23

Hi @marqusG, I try your code, but don't work. I use like you can see in snippet code. Maybe I do something wrong.
Please check. I will waiting for your new solution (off course in until time) for close the question.

Hi @trencH87, your code is correct.

Regards, JC

<?
$string = "http://www.pt.domain.com";
preg_match("/(?<=http:\/\/)(\w\w)(?=\/)|(?<=http:\/\/www\.)/", $string, $match);
if($match[0] == ""){
	echo "Wrong URL";
} else {
	echo "The URL:$match[0] is correct";
}
?>

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LVL 4

Assisted Solution

by:trencH87

trencH87 earned 700 total points

ID: 337474152010-09-23

In a function:

function checkSub($url) 
{
	$pieces = explode(".",$url);
	$check = (substr($pieces[0],0,4) == "http") ? substr($pieces[0],7) : $pieces[0];
	$subdomain = ($check == "www") ? $check.".".$pieces[1] : $check;
	$sub = substr($subdomain,4);
	
	if (strstr($subdomain,".")) {
		$msg = (strlen($sub) == 2 && ctype_alpha($sub)) ? $sub." : Success!" : $sub." : Failed!";
	} else {
		$msg = (strlen($subdomain) == 2 && ctype_alpha($subdomain)) ? $subdomain." : Success!" : $subdomain." : Failed!" ;
	}
	
	return $msg;
}

$subCheck = checkSub("http://pt.domain.com");
echo $subCheck;

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LVL 31

Expert Comment

by:Marco Gasi

ID: 337477622010-09-23

Fixed (a little change to regexp, the first because is more correct this way, the seond one to adjust to match subdomain if foolowed by a dot - in your first post subdomain was never followed by a dot):

<?php
$string = "http://www.pt.domain.com";
preg_match("/(?<=http:\/\/|http:\/\/www\.)(\w\w)(?=\/|\.)/", $string, $match);
if($match[0] == ""){
echo "Wrong URL";
} else {
echo "The URL:$match[0] is correct";
}
?>

Cheers

LVL 3

Author Comment

by:Pedro Chagas

ID: 337491342010-09-23

Hi again @marqusG, just one more pitch, which had already mentioned in earlier posts.
Like I tell before, the acronym just have 2 characters and this characters have to be alpha, not numeric. If I write: $string = "http://p3.domain.com"; the script recognize with a correct configuration, when is wrong configuration. Sub-domain just accept alpha characters (a-Z).

Hi trencH87, your example still correct (now a function).

Regards, JC

LVL 31

Assisted Solution

by:Marco Gasi

Marco Gasi earned 700 total points

ID: 337510342010-09-23

I'm very sorry for my inattention:

preg_match("/(?<=http:\/\/|http:\/\/www\.)[a-zA-Z]{2}(?=\/|\.)/", $string, $match);

Best

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