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Regex Javascript expression help

Posted on 2010-09-23
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Last Modified: 2012-05-10
I have a javascript function that validates email addresses (see attached).  The problem is it returns FALSE for an email address with a + (plus) in it, e.g. "+amerFandB@ihg.com".  Can someone give me the proper syntax to allow it to accept a + as a valid character?
//Returns TRUE if the passed string appears to be a valid e-mail address 

function isEmailAddressValid (passedEmail) { 

var a = (!(String(passedEmail)).search(/\b(^(\S+@).+((\.com)|(\.net)|(\.edu)|(\.mil)|(\.biz)|(\.gov)|(\.org)|(\.int)|(\.info)|(\.name)|(\.coop)|(\..{2,2}))$)\b/gi));        //general validity 

var b = (String(passedEmail).indexOf('@') == String(passedEmail).lastIndexOf('@'));                //only one @ 

var c = (String(passedEmail) == fullTrimString(passedEmail));                        //no whitespace 

return(a && b && c); 

}

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Question by:Paulconsulting
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Expert Comment

by:gurvinder372
ID: 33743578
try changing line number 3 to

var a = (!(String(passedEmail)).search(/\b(^(\+){0,1}(\S+@).+((\.com)|(\.net)|(\.edu)|(\.mil)|(\.biz)|(\.gov)|(\.org)|(\.int)|(\.info)|(\.name)|(\.coop)|(\..{2,2}))$)\b/gi));        


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Expert Comment

by:gurvinder372
ID: 33743586
do you want '+' to be allowed only at the beginning only? or else where also?
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Author Comment

by:Paulconsulting
ID: 33743670
begining only
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Author Comment

by:Paulconsulting
ID: 33743673
well rather before the @
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Expert Comment

by:gurvinder372
ID: 33743702
make it

var a = (!(String(passedEmail)).search(/\b(^([\S\+]+@).+((\.com)|(\.net)|(\.edu)|(\.mil)|(\.biz)|(\.gov)|(\.org)|(\.int)|(\.info)|(\.name)|(\.coop)|(\..{2,2}))$)\b/gi));        
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Author Comment

by:Paulconsulting
ID: 33743780
its almost there...its letting me put in a + after the @ sign that should not be allowed
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Expert Comment

by:gurvinder372
ID: 33743805
can you share the test data with me? thanks
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Author Comment

by:Paulconsulting
ID: 33743839
Should be allowed:
fdsa+@fdsa.com
fds+a@fdsa.com
+fdsa@fdsa.com
etc.  any + before the @ is ok

Should not be allowed:
fdsa@+fdsa.com
fdsa@fdsa+.com
fdsa@fdsa.+com
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Accepted Solution

by:
gurvinder372 earned 500 total points
ID: 33744076
this one worked for me
<html>
<body>

<script type="text/javascript">

function isEmailAddressValid (passedEmail) { 
var a = (!(String(passedEmail)).search(/(^(\S+@)[a-zA-Z0-9]+((\.com)|(\.net)|(\.edu)|(\.mil)|(\.biz)|(\.gov)|(\.org)|(\.int)|(\.info)|(\.name)|(\.coop)|(\..{2,2}))$)/gi));     
return a ; 
}
document.writeln(isEmailAddressValid("fdsa+@fdsa.com")); 
document.writeln(isEmailAddressValid("fds+a@fdsa.com")); 
document.writeln(isEmailAddressValid("+fdsa@fdsa.com")); 
document.writeln(isEmailAddressValid("fdsa@+fdsa.com")); 
</script>

</body>
</html>

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Author Closing Comment

by:Paulconsulting
ID: 33744126
Thanks for your help!
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Expert Comment

by:gurvinder372
ID: 33744146
thanks for the points :)
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