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Patrick O'DeaFlag for Ireland asked on

VBA to include only a-z in end string

Hi,
See below.
How do I remove all characters not in the range a-z or A-Z.
Essentially, I am looking for code to replace the line in bold below.

Dim sourcestring , destinationstring as string
sourcestring = "abc./ xyzABC"

**destinationstring = replace(sourcest......????
msgbox destinationstring shows   "abcxyzABC"



Microsoft ExcelVB Script

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Patrick O'Dea

8/22/2022 - Mon
ASKER CERTIFIED SOLUTION
patrickab

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SOLUTION
Ardhendu Sarangi

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ASKER
Patrick O'Dea

pari123,

I chose to use you code (as it suited my limited VBA ability).

However, it crashes at the line;

                    Mid(ws2.Range("C" & i), k, 1) = ""   ;

"Variable required - can't assign to this expression".

Any thought?
I guess it is saying that you can't assign a value to the middle of a string??  Is that right? What would be the syntax to simply replace the character with a "" ??





 For k = 1 To Len(ws2.Range("C" & i))
                If (Asc(Mid(ws2.Range("C" & i), k, 1)) >= 65 And Asc(Mid(ws2.Range("C" & i), k, 1)) <= 90) Or _
                   (Asc(Mid(ws2.Range("C" & i), k, 1)) >= 97 And Asc(Mid(ws2.Range("C" & i), k, 1)) <= 122) Or _
                   (Asc(Mid(ws2.Range("C" & i), k, 1))) = 32 Then
                Else
                    Mid(ws2.Range("C" & i), k, 1) = ""   
                End If
            Next k
Ardhendu Sarangi

Hi Dewsbury,

Can you please try this code -

regards,
Ardhendu
Sub cleanup()
strX = ""
For i = 1 To Cells(65536, "C").End(xlUp).Row
    For k = 1 To Len(Range("C" & i))
        'MsgBox (Mid(Range("C" & i), k, 1))
        If (Asc(Mid(Range("C" & i), k, 1)) >= 65 And Asc(Mid(Range("C" & i), k, 1)) <= 90) Or _
           (Asc(Mid(Range("C" & i), k, 1)) >= 97 And Asc(Mid(Range("C" & i), k, 1)) <= 122) Then
           strX = strX & Mid(Range("C" & i), k, 1)
        End If
    Next k
    Range("C" & i) = strX
    strX = ""
Next
End Sub

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patrickab

21Dewsbury,

I would have thought that having provided the VBA code, an example and a file illustrating how it works my very simple function 'bb' would be the easiest method to adopt.

To help I have commented the code below.

Patrick


Function bb(ByVal target As Range) As String
'declare variables
Dim i As Long
Dim str1 As String

'work through the 'target' string, character by character
For i = 1 To Len(target)
'convert each character to its Ascii value
    Select Case Asc(Mid(target, i, 1))
'if the Ascii value is between 65 and 90 (A-Z) then add it to the string str1
        Case 65 To 90
           str1 = str1 & Mid(target, i, 1)
'if the Ascii value is between 97 and 122 (a-z) then add it to the string str1
        Case 97 To 122
            str1 = str1 & Mid(target, i, 1)
    End Select
Next i
'make bb equal to str1
bb = str1

End Function

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ASKER
Patrick O'Dea

Thanks Patrickab,

You code is much appreciated.Points will be shared.
ASKER
Patrick O'Dea

Thanks all,

Problem solved !