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rgb192Flag for United States of America asked on

sum subtotal,total,cost

subtotal is derived line 12
debit is derived line 13
minitemid is derived line 14



if i.itemid==minitemid
then total=debit and subtotal=subtotal
else total=0 and subtotal=0


I am doing this because I only want the total and subtotal to be on one row
There can be many orderitems.itemid for one orders.orderid but there is only one total and subtotal per order




also want to find sum of subtotal as subtotalsum, total as totalsum, cost as costsum
select * from(
select o.dateordered,o.company,o.orderid,RTRIM ( LTRIM( o.billfirstname + ' ' + o.billlastname ) ) billfullname,o.email,o.itemid as oitemid 
,p.cost1,p.cost2,p.cost3,p.productid,p.title as ptitle 
,e.title as etitle 
,s.status 
,i.sku,i.quantity,i.itemid as iitemid 
,CASE sku 
WHEN p.internalsku1 THEN p.cost1*i.quantity 
WHEN p.internalsku2 THEN p.cost2*i.quantity 
WHEN p.internalsku3 THEN p.cost3*i.quantity 
ELSE 0 END as cost 
,(select sum(subtotal) from orderitems where orderid=o.orderid)as subtotal 
,(select SUM(debit) from payments where orderid=o.orderid and ( (type='Paypal' and 'confirmation'!='' and resultcode!='Denied' and resultcode!='unconfirmed') or (type!='Paypal') ) )as debit 
,(select min(itemid) from orderitems where orderid=o.orderid)as minitemid 
from orders o 
INNER JOIN orderitems i on i.orderid = o.orderid 
INNER JOIN products p on i.productid = p.productid 
left join ebaydata e on o.orderid = e.orderid 
left join sstatuses s on o.statusid=s.statusid 
where (o.dateordered between '11/01/2010' and '11/09/2010') 
AND o.orderid In (select orderid from orderitems i,Products P Where i.productid = p.productid and P.title LIKE '%sd%') 
and o.statusid in (10,90,110,260) 
and ( (company='company1'and o.itemid>0) or (company='company2'and o.itemid>0) or o.itemid=0 ) 
)Derived where debit>0 
order by orderid desc

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Microsoft SQL Server 2005

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Last Comment
rgb192

8/22/2022 - Mon
David Todd

Hi,

I don't see a question. What is your problem with the query?

Regards
  David
ASKER
rgb192

i want to find
sum of subtotal,
sum of total,
sum of cost
David Todd

Hi,

On line 1 replace select * from (
with  select sum( subtotal ), sum( total ), sum( cost ) from (

HTH
  David
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James Murphy
ASKER
rgb192

Msg 8127, Level 16, State 1, Line 1
Column "Derived.orderid" is invalid in the ORDER BY clause because it is not contained in either an aggregate function or the GROUP BY clause.
select sum(subtotal) from(
select o.dateordered,o.company,o.orderid,RTRIM ( LTRIM( o.billfirstname + ' ' + o.billlastname ) ) billfullname,o.email,o.itemid as oitemid 
,p.cost1,p.cost2,p.cost3,p.productid,p.title as ptitle 
,e.title as etitle 
,s.status 
,i.sku,i.quantity,i.itemid as iitemid 
,CASE sku 
WHEN p.internalsku1 THEN p.cost1*i.quantity 
WHEN p.internalsku2 THEN p.cost2*i.quantity 
WHEN p.internalsku3 THEN p.cost3*i.quantity 
ELSE 0 END as cost 
,(select sum(subtotal) from orderitems where orderid=o.orderid)as subtotal 
,(select SUM(debit) from payments where orderid=o.orderid and ( (type='Paypal' and 'confirmation'!='' and resultcode!='Denied' and resultcode!='unconfirmed') or (type!='Paypal') ) )as debit 
,(select min(itemid) from orderitems where orderid=o.orderid)as minitemid 
from orders o 
INNER JOIN orderitems i on i.orderid = o.orderid 
INNER JOIN products p on i.productid = p.productid 
left join ebaydata e on o.orderid = e.orderid 
left join sstatuses s on o.statusid=s.statusid 
where (o.dateordered between '11/01/2010' and '11/09/2010') 
AND o.orderid In (select orderid from orderitems i,Products P Where i.productid = p.productid and P.title LIKE '%sd%') 
and o.statusid in (10,90,110,260) 
and ( (company='company1'and o.itemid>0) or (company='company2'and o.itemid>0) or o.itemid=0 ) 
)Derived where debit>0 
order by orderid desc

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ASKER CERTIFIED SOLUTION
David Todd

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ASKER
rgb192

the sums are the same as the values

I want there to be one sum subtotal, one sum total(debit), one sum cost
David Todd

Hi,

I can't really comment without sample data.

If you want one total line, then instead of the previous instructions, remove the order by clause on line 25. I suggested commenting it out. If you had done this you would have solved your problem.

HTH
  David
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ASKER
rgb192

thanks.