Access SQL Count number of items per month

Posted on 2010-11-08
Medium Priority
Last Modified: 2012-05-10
Hi Experts,

I am new to SQL, and would like to know if there is an easy way to do the following:

I have a table called Builds, and the fields in it are BuildDate, Hull number, ShipType.

I want to make a chart that will plot the number of HullNumbers per month.

So for example, I want to select a range of Months, Say Jan 2010, to May 2010, and get a count of the number of HullNumbers  plotted on a line chart . I guess it is like a count of the records per month.

If I have a Chart called chartB, what would the SQL query look like if it was the datasource?

I know this is a pretty simple thing, but I have not had more than a few days with SQL, and am really finding it a little esoteric.

Thanks for your help.
Question by:WestCoastHip
  • 3
LVL 65

Accepted Solution

rockiroads earned 2000 total points
ID: 34089699
you could try something like this

SELECT COUNT(HullNumbers) AS TotalHullNumbers, Format(BuildDate,"MMM YYYY")
FROM Builds
GROUP BY Format(BuildDate,"MMM YYYY")

Create a new query in masaccess, go to sql view and paste this

Because we use COUNT we have to group all other fields
LVL 65

Expert Comment

ID: 34089703
Since your new to SQL, it might be a good idea to use the SQL wizard.

Have a butchers here as it should hopefully help you out http://office.microsoft.com/en-us/access-help/count-data-by-using-a-query-HA010096311.aspx

LVL 65

Expert Comment

ID: 34089709
Now one thing I forgot to add is the build date. The date obviously has a day number in it (assuming BuildDate is stored as a date field in the database). In order to extract just the month and year we make use of the format command and specify the strings MMM (for 3 character month) and YYYY (for 4 digit year). If you highlight the Format command then hit F1, it should bring up more info plus a list of other strings to use.

If BuildDate not saved as a date but just text with no day number then remove the Format, just leave it as BuildDate (in both uses SELECT and GROUP BY)

Author Closing Comment

ID: 34089719
Thanks for your help rocki! I appreciate your time, and the more I see the more I am learning.

Thanks again.

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