Compile Error

Posted on 2010-11-09
Last Modified: 2012-05-10
I am sure this is easy, I am trying to explore C++ using random websites and can not figure out why this will not compile.

I get the compile error at error C2660: 'SubExpression::parse' : function does not take 1 arrgument.

Thanks in advance

I have included subexpression as well
#include <iostream>

#include <fstream>

#include <strstream>

#include <string>

#include <vector>

using namespace std;

#include "expression.h"

#include "subexpression.h"

#include "symboltable.h"

#include "parse.h"

SymbolTable symbolTable;

void parseAssignments(strstream& in);

int main()


    const int SIZE = 256;

    Expression* expression;

    char paren, comma, line[SIZE];

    string program;

    ifstream fin("input.txt");

    while (true)




        fin.getline(line, SIZE);

        if (!fin)


        strstream in(line, SIZE);

        in >> paren;

        cout << line << " ";



            expression = SubExpression::parse(in); 

            in >> comma;  


            double result = expression->evaluate();

            cout << "Value = " << result << endl;    


        catch (exception& e)


              cout << "Standard exception: " << e.what() << endl;




    return 0;



void parseAssignments(strstream& in)


    char assignop, delimiter;

    string variable;

    double value;



        variable = parseName();

        in >> ws >> assignop >> value >> delimiter;

        symbolTable.insert(variable, value);


    while (delimiter == ',');


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#include <iostream>

using namespace std;

#include "expression.h"

#include "subexpression.h"

#include "operand.h"

#include "plus.h"

#include "minus.h"

#include "times.h"

#include "divide.h"

SubExpression::SubExpression(Expression* left, Expression* right)


    this->left = left;

    this->right = right;


Expression* SubExpression::parse()


    Expression* left;

    Expression* right;

    char operation, paren;


    left = Operand::parse();

    cin >> operation;

    right = Operand::parse();

    cin >> paren;

    switch (operation)


        case '+':

            return new Plus(left, right);

        case '-':

            return new Minus(left, right);

        case '*':

            return new Times(left, right);

        case '/':

            return new Divide(left, right);


    return 0;


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Question by:Chris Pfeiffer
LVL 86

Accepted Solution

jkr earned 500 total points
ID: 34097406
Well, as your snippet indicates, 'Expression* SubExpression::parse()' in fact take no arguments at all.

So, change

            expression = SubExpression::parse(in);

(line 37 in the 1st snippet) to read

            expression = SubExpression::parse();

and the error should go away.

Author Comment

by:Chris Pfeiffer
ID: 34097430
Man, its time to go to sleep.. Thanks for that, as soon as I read it I wondered how I missed it..

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