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Compile Error

Posted on 2010-11-09
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Last Modified: 2012-05-10
I am sure this is easy, I am trying to explore C++ using random websites and can not figure out why this will not compile.

I get the compile error at error C2660: 'SubExpression::parse' : function does not take 1 arrgument.

Thanks in advance

I have included subexpression as well
#include <iostream>
#include <fstream>
#include <strstream>
#include <string>
#include <vector>
using namespace std;

#include "expression.h"
#include "subexpression.h"
#include "symboltable.h"
#include "parse.h"

SymbolTable symbolTable;

void parseAssignments(strstream& in);

int main()
{
    const int SIZE = 256;
    Expression* expression;
    char paren, comma, line[SIZE];
    string program;

    ifstream fin("input.txt");
    while (true)
    {
    
        symbolTable.init();
        fin.getline(line, SIZE);
        if (!fin)
            break;
        strstream in(line, SIZE);
        in >> paren;
        cout << line << " ";
        try
        {
            expression = SubExpression::parse(in); 
            in >> comma;  
            parseAssignments(in);
            double result = expression->evaluate();
            cout << "Value = " << result << endl;    
        }
        catch (exception& e)
        {
              cout << "Standard exception: " << e.what() << endl;
        }
        
    }
    return 0;
    
}

void parseAssignments(strstream& in)
{
    char assignop, delimiter;
    string variable;
    double value;
    do
    {
        variable = parseName();
        in >> ws >> assignop >> value >> delimiter;
        symbolTable.insert(variable, value);
    }
    while (delimiter == ',');
}

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#include <iostream>
using namespace std;

#include "expression.h"
#include "subexpression.h"
#include "operand.h"
#include "plus.h"
#include "minus.h"
#include "times.h"
#include "divide.h"

SubExpression::SubExpression(Expression* left, Expression* right)
{
    this->left = left;
    this->right = right;
}

Expression* SubExpression::parse()
{
    Expression* left;
    Expression* right;
    char operation, paren;
    
    left = Operand::parse();
    cin >> operation;
    right = Operand::parse();
    cin >> paren;
    switch (operation)
    {
        case '+':
            return new Plus(left, right);
        case '-':
            return new Minus(left, right);
        case '*':
            return new Times(left, right);
        case '/':
            return new Divide(left, right);
    }
    return 0;
}

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Question by:Chris Pfeiffer
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2 Comments
 
LVL 86

Accepted Solution

by:
jkr earned 500 total points
ID: 34097406
Well, as your snippet indicates, 'Expression* SubExpression::parse()' in fact take no arguments at all.

So, change

            expression = SubExpression::parse(in);

(line 37 in the 1st snippet) to read

            expression = SubExpression::parse();

and the error should go away.
0
 
LVL 2

Author Comment

by:Chris Pfeiffer
ID: 34097430
Man, its time to go to sleep.. Thanks for that, as soon as I read it I wondered how I missed it..
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