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Compile Error

Posted on 2010-11-09
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Last Modified: 2012-05-10
I am sure this is easy, I am trying to explore C++ using random websites and can not figure out why this will not compile.

I get the compile error at error C2660: 'SubExpression::parse' : function does not take 1 arrgument.

Thanks in advance

I have included subexpression as well
#include <iostream>

#include <fstream>

#include <strstream>

#include <string>

#include <vector>

using namespace std;



#include "expression.h"

#include "subexpression.h"

#include "symboltable.h"

#include "parse.h"



SymbolTable symbolTable;



void parseAssignments(strstream& in);



int main()

{

    const int SIZE = 256;

    Expression* expression;

    char paren, comma, line[SIZE];

    string program;



    ifstream fin("input.txt");

    while (true)

    {

    

        symbolTable.init();

        fin.getline(line, SIZE);

        if (!fin)

            break;

        strstream in(line, SIZE);

        in >> paren;

        cout << line << " ";

        try

        {

            expression = SubExpression::parse(in); 

            in >> comma;  

            parseAssignments(in);

            double result = expression->evaluate();

            cout << "Value = " << result << endl;    

        }

        catch (exception& e)

        {

              cout << "Standard exception: " << e.what() << endl;

        }

        

    }

    return 0;

    

}



void parseAssignments(strstream& in)

{

    char assignop, delimiter;

    string variable;

    double value;

    do

    {

        variable = parseName();

        in >> ws >> assignop >> value >> delimiter;

        symbolTable.insert(variable, value);

    }

    while (delimiter == ',');

}

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#include <iostream>

using namespace std;



#include "expression.h"

#include "subexpression.h"

#include "operand.h"

#include "plus.h"

#include "minus.h"

#include "times.h"

#include "divide.h"



SubExpression::SubExpression(Expression* left, Expression* right)

{

    this->left = left;

    this->right = right;

}



Expression* SubExpression::parse()

{

    Expression* left;

    Expression* right;

    char operation, paren;

    

    left = Operand::parse();

    cin >> operation;

    right = Operand::parse();

    cin >> paren;

    switch (operation)

    {

        case '+':

            return new Plus(left, right);

        case '-':

            return new Minus(left, right);

        case '*':

            return new Times(left, right);

        case '/':

            return new Divide(left, right);

    }

    return 0;

}

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0
Comment
Question by:Chrispy2811
2 Comments
 
LVL 86

Accepted Solution

by:
jkr earned 500 total points
Comment Utility
Well, as your snippet indicates, 'Expression* SubExpression::parse()' in fact take no arguments at all.

So, change

            expression = SubExpression::parse(in);

(line 37 in the 1st snippet) to read

            expression = SubExpression::parse();

and the error should go away.
0
 
LVL 2

Author Comment

by:Chrispy2811
Comment Utility
Man, its time to go to sleep.. Thanks for that, as soon as I read it I wondered how I missed it..
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