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what is the meaning of const at the end of the class member function

Posted on 2010-11-09
Medium Priority
Last Modified: 2012-05-10
hi all,

I am not sure whether my title describe the problem correctly or not. Apologise if i have not.

I have a class called CustLoaderFactory which is derived from TargetFactory and ObjectCollector class.

class CustLoaderFactory : public TargetFactory<TsfLoader>, ,public ObjectCollector<TsfLoader>

by the way, may i know what is the purpose of <TsfLoader> in above code?

then in both TargetFactory and ObjectCollector class, it declared the member function with a const at the end.

virtual int func1(char *a, const void *b) = 0;
what is the purpose of the const 0? And how do i declare it in my body program?

header file
class a : public b<TsfLoader>, ,public c<TsfLoader>
virtual int func 1(char *1a, const void *1b) = 0;

body code
int a::func1(char *1a, const void *1b)
    strcpy(1a, (char *)1b);
    return 0;

So, how do i call the func1 from my body code since it has a const at the back.

Beside that, since class a derive from class b and class c. by writing my own definition in body code for func1, am i  overiding the original definition?

I am testing out some sample code to get more understanding on the c++ OOP.
Thank you in advance.
Question by:gagajanice
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LVL 40

Accepted Solution

evilrix earned 500 total points
ID: 34098735
This explains all about const member functions.
LVL 40

Expert Comment

ID: 34098741
>> by the way, may i know what is the purpose of  in above code?

It's a template class so TsfLoader is the template parameter

Author Comment

ID: 34099099

the const that i have after the class member function is not a suffix const but a const integer:

virtual int func1(char *a, const void *b) = 0; (equal to integer "0").

Are they the same?
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LVL 32

Assisted Solution

phoffric earned 500 total points
ID: 34099109
The 0 is a special symbol in this context meaning that the function, func1, is not only a virtual function, but is is also a pure virtual function.

"In C++, pure virtual functions are declared using a special syntax [ = 0 ] as demonstrated below."

class Abstract {
   virtual void pure_virtual() = 0;

LVL 32

Expert Comment

ID: 34099119
Inclusion of a pure virtual function in a class makes that class abstract. FYI - an abstract class cannot be instantiated.

Assisted Solution

by:Subrat (C++ windows/Linux)
Subrat (C++ windows/Linux) earned 500 total points
ID: 34099781
In your code no where I found 'const' at the end of the class member function.

Something regarding const....
I'm giving you one ex:

class A {
     int a;
      void SetData(int x){
          a = x;

      int  GetData( ) const {
          // a = 20; -------------------------------------------> Gives error
            retun a;

If using const after member function as shown above, then that function can't modify any data member of that class. Here in reality we don't want GetData() to modify the data members, So making it const.


Assisted Solution

Xper4net earned 500 total points
ID: 34101625
Adding to Subrat2009 comment: in a const method like GetData, you are also restricted by calling only others const methods.
For example:
int GetData const {
// SetData(20) ------------> Gives error too !

But in C++, with most compilers, there's a workaround :
int GetData const{
((A*)this)->SetData(20) ; // yes, it works ! But it's not a good practice...

Author Closing Comment

ID: 34108380
hi all,

sorry for getting back to you all on this a bit late. this is because i am going through the link provided by you all yesterday.

actually, i was asking what is the purpose of having '= 0' at the back of the member function.

thanks phoffric for telling me is a special syntax of pure virtual function.

I somehow manage to compile my program with the guidance from you all.

Thank you very much. Have a nice day.
LVL 32

Expert Comment

ID: 34108390
One big step towards C++ mastery :)
Good luck learning!

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