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SQL Query Help

Posted on 2010-11-10
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Last Modified: 2012-05-10
SQL Server 2005 table:

ID   NewID
01    A01
02    A02
03   A031
03   A032
03   A033
03   A034
04   A041
04  A04 etc.  (NewId is unique)

Desired output:
ID  NewID1 NewID2 NewID3 NewID4 NewID5
01    A01
02    A02
03   A031    A032    A033     A034
04   A041      A04

Do I have to set in advance how many NewID columns are in the output?
Can it be dynamic?

Thank you very much!

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Question by:larisa1970
4 Comments
 
LVL 8

Expert Comment

by:kingjely
ID: 34108924


Hi Larisa
In mysql this would do what you need.. I'm not sure if it will work in mssql but worth a go

SELECT ID, GROUP_CONCAT(NEWID)
FROM YOURTABLE
GROUP BY ID
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LVL 2

Expert Comment

by:marat-oz
ID: 34110131
try this, but number of possible NEWIDs is hardcoded

WITH T (ID, [NEWID], GID)
AS
(
select *, row_number() over (partition by ID order by ID, [NewID])
from <YourTable>
)
select t1.ID, COALESCE(NEWID1,'') NEWID1, COALESCE(NEWID2,'') NEWID2, COALESCE(NEWID3,'') NEWID3, COALESCE(NEWID4,'') NEWID4, COALESCE(NEWID5,'') NEWID5
from  
(select ID, NEWID1 = [NewID] from T where t.GID = 1) t1
LEFT JOIN
(select ID, NEWID2 = [NewID] from T where t.GID = 2) t2 on t1.ID = t2.ID
LEFT JOIN
(select ID, NEWID3 = [NewID] from T where t.GID = 3) t3 on t1.ID = t3.ID
LEFT JOIN
(select ID, NEWID4 = [NewID] from T where t.GID = 4) t4 on t1.ID = t4.ID
LEFT JOIN
(select ID, NEWID5 = [NewID] from T where t.GID = 5) t5 on t1.ID = t5.ID

0
 
LVL 6

Expert Comment

by:dan_mason
ID: 34110952
This will give you the number of columns needed, and create them...
DECLARE @numCol int, @counter int=1, @sql varchar(200)
CREATE TABLE #output (ID char(2))
DECLARE @input table (ID char(2),NewID varchar(5))
INSERT @input (ID,NewID)
VALUES
('01','A01'),('02','A02'),('03','A031'),('03','A032'),('03','A033'),('03','A034'),('04','A041')

INSERT #output (ID)
SELECT DISTINCT ID FROM @input

SELECT @numCol= MAX(n) FROM(SELECT(COUNT(1)) as n FROM @input GROUP BY ID) a

WHILE @counter<=@numCol
	BEGIN
		SET @sql='ALTER TABLE #output ADD NewID'+CAST(@counter as varchar)+' varchar(5)'
		EXEC (@sql)
		SET @counter=@counter+1
	END

SELECT * FROM #output
DROP TABLE #output

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LVL 41

Accepted Solution

by:
ralmada earned 500 total points
ID: 34112243
You don't have to ALTER your table to do that.
I assume you don't know how many NewID you will have there per ID correct so basically you don't know how many columns you will need. Hence, you have to go with dynamic SQL. Check the below:

declare @strSQL varchar(max)

declare @cols varchar(max)



set @cols = stuff((select distinct 

			'], [' + cast(row_number() over (partition by id order by [NewID]) as varchar)

		from yourtable

		for xml path('')), 1, 2, '') + ']'



set @strSQL = 	' select id, ' + @cols +

		' from (select	id, 

				[NewID],

				row_number() over (partition by ID order by NewID) rn

			from yourtable

		 ) o

		pivot (max([NewID]) for rn in (' + @cols + ')) p'



exec(@strSQL)

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