Solved

getElementByClass in a HTML

Posted on 2010-11-10
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1,550 Views
Last Modified: 2012-05-10
I have a HTML webpage with the 3 classes.-sidebar1 is one class

Ia m trying to do this:
     var Height = document.getElementByClass('sidebar1').offsetHeight;

This is not working.
Can you please let me know how I can get the offset of a Class?

similarly I am trying to use the following function.
document.getElementByClass('sidebar1').style.height  which is also not working
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Question by:vkchaitu82
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19 Comments
 
LVL 58

Expert Comment

by:cyberkiwi
ID: 34108451
getElementsByClassName( name )

This gives you an array that you can work through
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Author Comment

by:vkchaitu82
ID: 34108467
Thankq.
can you please elaborate on this? i am not clear!!!
0
 
LVL 51

Expert Comment

by:Huseyin KAHRAMAN
ID: 34108481
try

var Height = document.getElementByClass('sidebar1')[0].offsetHeight;
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Author Comment

by:vkchaitu82
ID: 34108501
thankq.
is it  document.getElementByClass (or)  document.getElementsByClass??
also I have so many classes (3). so what is this [0] stand for?
0
 
LVL 51

Expert Comment

by:Huseyin KAHRAMAN
ID: 34108514
I found this function
<div id=d1 class=a width=100>a</div>
<div id=d2 class=b>b</div>
<div id=d3 class=b>b</div>
<div id=d4 class=a width=200>a</div>

<script>
function getElementsByClassName(classname, node)  {
    if(!node) node = document.getElementsByTagName("body")[0];
    var a = [];
    var re = new RegExp('\\b' + classname + '\\b');
    var els = node.getElementsByTagName("*");
    for(var i=0,j=els.length; i<j; i++)
    if(re.test(els[i].className))a.push(els[i]);
    return a;
}

var h1 = getElementsByClassName("a",document)[0].offsetHeight;
var h2 = getElementsByClassName("a",document)[1].offsetHeight;
alert(h1 + " - " + h2);
</script>

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LVL 51

Accepted Solution

by:
Huseyin KAHRAMAN earned 375 total points
ID: 34108542
use provided function above and use

var h1 = getElementsByClassName("a",document.body)[0].offsetHeight;
var h2 = getElementsByClassName("a",document.body)[1].offsetHeight;

or better if you know where are these elements, provide the container node as second parameter

var myContainer = document.getElementById("myContainerID");
var h1 = getElementsByClassName("a", myContainer)[0].offsetHeight;
var h2 = getElementsByClassName("a", myContainer)[1].offsetHeight;
0
 

Author Comment

by:vkchaitu82
ID: 34108562
Thanks Hainkut.
I am still not clear with the array/a/Mycontainter?

I think a=sidebar1 (my class name)
what are the other 2?
0
 
LVL 7

Expert Comment

by:wdfdo1986
ID: 34108716
try with this
var arr = getElementsByClassName('sidebar1');
for (var i = 0 ; i < arr.length ; i ++ ){
  var Height = document.getElementsByClassName('sidebar1').height;
 //do what u want to do with height
}
0
 
LVL 51

Expert Comment

by:Huseyin KAHRAMAN
ID: 34108737
just use the function above with these lines

var h1 = getElementsByClassName("a",document.body)[0].offsetHeight;
var h2 = getElementsByClassName("a",document.body)[1].offsetHeight;

if your elements are say in a div with id=myContainerID

<div id=myContainerID>
...
</div>

then you can use second sample to speed up element searching... here is both usage together
<div id=myContainerID>
<div id=d1 class=a>a</div>
<div id=d2 class=b>b</div>
<div id=d3 class=b>b</div>
<div id=d4 class=a>a</div>
</div>

<script>
function getElementsByClassName(classname, node)  {
    if(!node) node = document.getElementsByTagName("body")[0];
    var a = [];
    var re = new RegExp('\\b' + classname + '\\b');
    var els = node.getElementsByTagName("*");
    for(var i=0,j=els.length; i<j; i++)
    if(re.test(els[i].className))a.push(els[i]);
    return a;
}

var h1 = getElementsByClassName("a",document.body)[0].offsetHeight;
var h2 = getElementsByClassName("a",document.body)[1].offsetHeight;
alert(h1 + " - " + h2);

var myContainer = document.getElementById("myContainerID");
var h1 = getElementsByClassName("a",myContainer)[0].offsetHeight;
var h2 = getElementsByClassName("a",myContainer)[1].offsetHeight;
alert(h1 + " - " + h2);
</script>

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0
 

Author Comment

by:vkchaitu82
ID: 34109413
My element is in div = class.

 var Height = document.getElementsByClassName('sidebar1')[0].offsetHeight;
    document.getElementsByClassName('content')[0].style.height = Height + "px" ;

Both worked for me .I did noting else,
The Question I have is :
what does array[0] stand here?..I am really confused.
0
 
LVL 7

Expert Comment

by:wdfdo1986
ID: 34109967
ok
When u say getElementsByClassName it will return an array of objects whose class name is that name u given.
I hope u know that there can be several tags with same classname.
So it will return the array that contains the classname u given.
If u use it only for once then that array will only contain one element.
If u use more there will be more elements in the array.
0
 
LVL 5

Assisted Solution

by:SimonDard
SimonDard earned 125 total points
ID: 34110224
I recommend checking out jQuery for this.

If you have not heard of jQuery before: at it's core it is a relatively small library that gives you easy access to elements by id, class, type etc. making code easier to read and understand.

Your first question in jQuery would be: $(".sidebar1").height();
Changing it is as easy as:  $(".content").css("height",  ($(".sidebar1").height())+"px");

As you can see: no fiddling around with arrays here.
0
 
LVL 51

Assisted Solution

by:Huseyin KAHRAMAN
Huseyin KAHRAMAN earned 375 total points
ID: 34112008
but

document.getElementsByClassName('...)

does not exists, no such functiuon... what browsers are you using?
Thats why I posted the custom function... it returns you an array (a 0 based index of objects)
when it finds one lement, you get it by adding [0] to return value...

var divs =  getElementsByClassName("myDataDiv", document.body);
if (divs.length>0) {
 var div1=divs[0];
...
}
0
 

Author Comment

by:vkchaitu82
ID: 34112095
wdfdo1986- Thanks f the reply.
I am very new to javascript. can you tell me the what are the serveraltags with the given class name?

Is there any restrictions on the Browser to use this API?
As it is java script I think that will not be the case. but want to confirm.
0
 

Author Comment

by:vkchaitu82
ID: 34112120
HainKurt:
I am using crome.
Initially I also taught it is not there. but it worked in Crome/Firefox.

In IE it is not working?
0
 

Author Comment

by:vkchaitu82
ID: 34112151
Looks I am back to the problem.
so here are my questions again.

1) I am very new to javascript. can you tell me the what are the serveraltags with the given class name?

2) the script does not work in IE. should I look into jquery?
0
 
LVL 5

Expert Comment

by:SimonDard
ID: 34113074
1) getElementsByClassName gives you all the elements ('tags') using that class. Remember that several elements can share the same class.

2) jQuery is cross browser compatible, so looking into jQuery will help. Also, since you're new to javascript, using jQuery will make your work easier, although it doesn't hurt to know the underlying principles.
0
 
LVL 51

Assisted Solution

by:Huseyin KAHRAMAN
Huseyin KAHRAMAN earned 375 total points
ID: 34115380
the function I provided before, getElementsByClassName, should work fine in all browsers... why do you say it is not working? I tested it in IE

function getElementsByClassName(classname, node)  {
    if(!node) node = document.getElementsByTagName("body")[0];
    var a = [];
    var re = new RegExp('\\b' + classname + '\\b');
    var els = node.getElementsByTagName("*");
    for(var i=0,j=els.length; i<j; i++)
    if(re.test(els[i].className))a.push(els[i]);
    return a;
}
0
 
LVL 7

Expert Comment

by:wdfdo1986
ID: 34119506
I think I gave u a solution which assist u.
Although selection is urs I am worried about not rating my answer under assisted solution.
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