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convert to 0.00

Posted on 2010-11-11
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Last Modified: 2012-05-10
93.06  
93.01  
924,95
355.24  
355,96
355,41
2.245,82
2.074,95
2.034,95  
2,579.70
1.284,81  
1.284,81  
1.275,81  

want to find sum of this varchar column
there are
,
and
both
. and ,
large numbers

I would like to convert all to 0.00
0
Comment
Question by:rgb192
  • 3
  • 2
  • 2
  • +2
9 Comments
 
LVL 7

Accepted Solution

by:
mkobrin earned 167 total points
ID: 34111178
sum(convert(tofloat, columnName))

Should do it for you or you can use a convert to decomal with the required settings as well.
0
 

Author Comment

by:rgb192
ID: 34111258
Msg 243, Level 16, State 1, Line 2
Type tofloat is not a defined system type.
0
 
LVL 7

Expert Comment

by:mkobrin
ID: 34111286
Sorry (Using C# syntax)

Try sum(convert(float, columnName))
0
 

Author Comment

by:rgb192
ID: 34111639
Msg 8114, Level 16, State 5, Line 1
Error converting data type varchar to float.
0
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LVL 19

Expert Comment

by:Bhavesh Shah
ID: 34111644
0
 
LVL 32

Expert Comment

by:Erick37
ID: 34111671
The assumption here is that there will always be 2 decimal places in the numbers.
The following removes all '.' and ',' and then converts to a number, divides by 100 to get the decimal back in the right place and then sums the column.

SELECT
      CAST(SUM(CONVERT(NUMERIC(19,2), REPLACE(REPLACE(YourColumn,',',''),'.','')) / 100) AS NUMERIC(19,2))
FROM yourtable
0
 
LVL 32

Assisted Solution

by:Erick37
Erick37 earned 167 total points
ID: 34111851
OK, this will take care of the case when there is a mix of number with 2 decimal places and numbers without decimal places e.g. 123.45 and 123

SELECT
      CAST(
            SUM( CASE PATINDEX('__[,|.]%',REVERSE(YourColumn))
                  WHEN 1 THEN CONVERT(NUMERIC(19,2), REPLACE(REPLACE(YourColumn,',',''),'.','')) / 100
                  ELSE CONVERT(NUMERIC(19,2), REPLACE(REPLACE(YourColumn,',',''),'.',''))
                  END)
      AS NUMERIC(19,2)) AS Total
FROM @YourTable
0
 
LVL 4

Assisted Solution

by:parthmalhan
parthmalhan earned 166 total points
ID: 34144509
Try the following Code:

select sum((convert(money,columnname))) from tablename
0
 

Author Closing Comment

by:rgb192
ID: 34220301
thanks
0

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