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T-SQL string manipulation without using Loop?  T-SQL support regular expressions?  (SQL Server 2005)

Posted on 2010-11-11
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Last Modified: 2012-06-27
I'm trying to write an efficient SQL statement to do the following string replacement on a single column in a table (see blow):

FIND THIS: 0. DISC *:
REPLACE WITH: <strong>DISC *:</strong>

where * is an integer from 1 to 10.

In other words, I wish to remove the "0." in front of the word "DISC" and make the actual disc number bold.

(There are other rows in the table that don't start with text "0. DISC" at all.)

There will be multiple occurrences of the search string in each row.

Any ideas for how to pull this off efficiently?  My loop (below) runs just fine but is slow as molasses.  Plus, it just feels "wrong" to use a loop! ;)   I wish T-SQL nativity supported regular expressions.

I may end up taking an entirely different approach to solving this problem but before I do I was hoping someone had a quick solution in mind that could help me.

sample INPUT tracks row:

0. DISC 1: text here 0. DISC 2: text here 0. DISC 3: text here 1. some other data untouched 2. yet another row untouched

sample RESULT tracks row:

<strong>DISC 1:</strong> text here <strong>DISC 2:</strong> text here <strong>DISC 3:</strong> text here 1. some other data untouched 2. yet another row untouched
create table CompactDiscs (
    id int,
    tracks varchar(4000)   
)

Inefficient Version:
declare @counter int
set @counter = 1
while @counter <= 10
begin
	print 'The counter is ' + cast(@counter as char)

	update CompactDiscs set tracks=REPLACE(tracks,'0. DISC '+cast(@counter as varchar)+':','<strong>DISC '+cast(@counter as varchar)+'</strong>');
	set @counter = @counter + 1
end

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Question by:ZuZuPetals
2 Comments
 
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Accepted Solution

by:
bhess1 earned 500 total points
ID: 34114364
The difficulty with this one was the possibility of the 10 value.  Here is one solution I came up with:


CREATE TABLE #t (

	id int IDENTITY,

	tracks varchar(50)

	)

INSERT INTO #t(tracks) VALUES ('ewin 0. DISC 1: asdoab')

INSERT INTO #t(tracks) VALUES ('0. DISC 2:')

INSERT INTO #t(tracks) VALUES ('0. DISC 3:a sdfabsuif')

INSERT INTO #t(tracks) VALUES ('0. DISC 4:')

INSERT INTO #t(tracks) VALUES ('asnwr 0. DISC 5:')

INSERT INTO #t(tracks) VALUES ('0. DISC 6:')

INSERT INTO #t(tracks) VALUES ('0. DISC 7:')

INSERT INTO #t(tracks) VALUES ('0. DISC 8:')

INSERT INTO #t(tracks) VALUES ('0. DISC 9:')

INSERT INTO #t(tracks) VALUES ('0. DISC 10:')

INSERT INTO #t(tracks) VALUES ('0. DISC 191:');



WITH tfx AS (

SELECT 

	id,

	PATINDEX('%0. DISC [123456789]:%', tracks) o9,

	PATINDEX('%0. DISC 10:%', tracks) o10

FROM #t

WHERE tracks LIKE '%0. DISC [123456789]:%'

	OR tracks LIKE '%0. DISC 10:%'

)

UPDATE #t

SET tracks = 

	CASE 

		WHEN o9 = 0

			THEN

				CASE

					WHEN o10 = 1

						THEN ''

					ELSE LEFT(tracks, o10-1)

				END + '<strong>' + SUBSTRING(tracks, o10+3, 8) + '</strong>' + SUBSTRING(tracks, o10+11, LEN(tracks))

		ELSE 

			CASE

				WHEN o9 = 1

					THEN ''

				ELSE LEFT(tracks, o9-1)

			END + '<strong>' + SUBSTRING(tracks, o9+3, 7) + '</strong>' + SUBSTRING(tracks, o9+10, LEN(tracks))

	END

FROM #t 

INNER JOIN tfx

	ON tfx.id = #t.id

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Author Closing Comment

by:ZuZuPetals
ID: 34122599
I never thought of using PatIndex().  Thanks for putting so much work into this!!!
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