Link to home
Create AccountLog in
Avatar of bigjdve
bigjdve

asked on

PHP Fatal error: Call to a member function fetch_assoc() on a non-object on line 19

This work with a die statement.  I put the die statement for testing.  But once I remove the die statement for it to continue processing, I get the php fatal error.  I tried to free the result set or close it, but it is still complaining.

See my code:

$mysqli = @new mysqli($db_host, $db_username, $db_password, $db_name);

$sql = "select * from table1";
$dataIndex = $mysqli->query($sql);

while ($result = $dataIndex->fetch_assoc())
{
      $field1 = $result['index_short_name']."_field1";
      $field2 = $result['index_short_name']."_field2";
      
      $sqlData = "select new_date, ".$field1.", ".$field2."  from table2";      
      $dataFund = $mysqli->query($sqlData);
      
      while ($row = $dataFund->fetch_assoc())
      {
            $line = "";
            $line .=  $row['new_date'].",".$row[$field1].",".$row[$field2]."\n";
            echo "<p>".$line."</p>";
            
      }
      die("here");
}

I replace the die("here") with $dataFund->close() and still error.
ASKER CERTIFIED SOLUTION
Avatar of Dave Baldwin
Dave Baldwin
Flag of United States of America image

Link to home
membership
Create an account to see this answer
Signing up is free. No credit card required.
Create Account
You should put error check to each query you have

$dataIndex = $mysqli->query($sql);
if (!$dataIndex ) {
   die('Invalid query: ' . mysql_error());
}


$dataFund = $mysqli->query($sqlData);
if (!$dataFund ) {
   die('Invalid query: ' . mysql_error());
}

I think one of those loops might meet empty result and it causes that error
Avatar of bigjdve
bigjdve

ASKER

Basically, you can not do nested queries.