Solved

vb.net pass structure filed into function

Posted on 2010-11-12
6
356 Views
Last Modified: 2012-05-10
I want to pass the data.diff field into the function. This works in Matlab. :) The IDE says that " 'diff' is not a member of 'system.array' ". The data structure is redim'ed and filled with data in code not shown. How do you get the field into the function?

'create structure to hold switch event data
Structure SWEvent
     Dim switch As String
     Dim time As Double
     Dim diff As Double
End Structure

'create data structure
Private data(0) As SWEvent

'my function
Public Function ArrayAverage(ByVal NumericArray() As Double) As Double
...
End Function

'trying to pass filed to function
dim mean as Double
mean = ArrayAverage(data.diff)

Open in new window

0
Comment
Question by:jramshur
  • 4
  • 2
6 Comments
 
LVL 37

Expert Comment

by:TommySzalapski
ID: 34118773
You created data as an array of SWEvents. Take out the (0) or do data(1).diff.
0
 
LVL 37

Expert Comment

by:TommySzalapski
ID: 34118793
Oh, wait, I see what you are doing. Hang on.
0
 
LVL 37

Expert Comment

by:TommySzalapski
ID: 34118854
Okay, pass the whole thing into the function ArrayAverage(data) and do this
'my function
Public Function ArrayAverage(ByVal EventArray() As SWEvent) As Double
...For Each e in EventArray blah blah sum = sum + e.diff
End Function

Open in new window

0
Gigs: Get Your Project Delivered by an Expert

Select from freelancers specializing in everything from database administration to programming, who have proven themselves as experts in their field. Hire the best, collaborate easily, pay securely and get projects done right.

 

Author Comment

by:jramshur
ID: 34119125
I was considering that solution, but wanted to pass the field so that I can use other functions I have. Trying to keep from modifying several functions. Let me ask another question: how do you assign a numeric array to a structure field as below? This could solve my issues.

dim d() as double
d = data.diff

Open in new window

.
0
 
LVL 37

Accepted Solution

by:
TommySzalapski earned 500 total points
ID: 34119139
No you can't. The array does not have a .diff property ever for anything.
If you really want just the .diff members you'll have to pull them out into a new array.
Something like:
Dim numericArray(UBound(data)) As Integer

For i = 1 To UBound(data)
  numericArray(i) = data(i).diff
Next

Open in new window

0
 

Author Comment

by:jramshur
ID: 34128112
Thanks. That works, but I'm disappointed that there isn't more array/matrix support in vb.net.
0

Featured Post

Courses: Start Training Online With Pros, Today

Brush up on the basics or master the advanced techniques required to earn essential industry certifications, with Courses. Enroll in a course and start learning today. Training topics range from Android App Dev to the Xen Virtualization Platform.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

It’s quite interesting for me as I worked with Excel using vb.net for some time. Here are some topics which I know want to share with others whom this might help. First of all if you are working with Excel then you need to Download the Following …
Creating an analog clock UserControl seems fairly straight forward.  It is, after all, essentially just a circle with several lines in it!  Two common approaches for rendering an analog clock typically involve either manually calculating points with…
Microsoft Active Directory, the widely used IT infrastructure, is known for its high risk of credential theft. The best way to test your Active Directory’s vulnerabilities to pass-the-ticket, pass-the-hash, privilege escalation, and malware attacks …
This video shows how to use Hyena, from SystemTools Software, to bulk import 100 user accounts from an external text file. View in 1080p for best video quality.

774 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question