?
Solved

How Do I Pass a Value from a Scriplet Variable to an iReport Parameter?

Posted on 2010-11-12
8
Medium Priority
?
2,519 Views
Last Modified: 2012-05-10
I wrote a scriptlet that executes an Oracle SQL function called "get_bps_rept_gn". It returns a number that I am trying to pass to an iReport 3.5.1 parameter. The parameter is called $P{bps_rept_gn}. Whenever I try to pass the value to this parameter, the parameter displays as null. I can successfully pass the value to a variable of the same name as the parameter ($V{bps_rept_gn}. This value displays in the report. I'm new to scriplets so I may be missing something in the syntax.
/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

package com.BPS_scriptlet_pg;

import net.sf.jasperreports.engine.JRDefaultScriptlet;
import net.sf.jasperreports.engine.JRScriptletException;
/*import net.sf.jasperreports.engine.query.JRQueryExecuter;*/
import java.sql.Connection;
import java.sql.SQLException;
import java.sql.CallableStatement;
import java.util.HashMap;
import java.util.Map;


/**
 *
 * @author 
 */
public class BPS022_scriptlet extends JRDefaultScriptlet {
    
    Connection con;



@Override
    public void afterReportInit() throws JRScriptletException
    {
        con = (Connection)this.getParameterValue("REPORT_CONNECTION");

        try{
        seeCon(con); 


Integer pi_rept_gn2 = 0;

CallableStatement cs4 = con.prepareCall("{? = call get_bps_rept_gn}");

cs4.registerOutParameter(1, java.sql.Types.NUMERIC);

cs4.executeUpdate();

pi_rept_gn2 = cs4.getInt(1);

this.setVariableValue("bps_rept_gn", pi_rept_gn2);

//parametersMap.put("bps_rept_gn", pi_rept_gn2.intValue());
Map parameters = new HashMap();
		parameters.put("bps_rept_gn", pi_rept_gn2);



        } catch (SQLException e){
            System.out.println("Caught SQL Exception: " + e.getErrorCode());
        }


        System.out.flush();
    }
  
    public void seeCon (Connection c) throws SQLException
    {
        System.out.println("Con is closed? :" + c.isClosed());
    }


}

Open in new window

0
Comment
Question by:shellybelly999
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
  • 4
  • 4
8 Comments
 
LVL 27

Expert Comment

by:mrcoffee365
ID: 34128157
I see where you put the new value into a new HashMap of parameters:
Map parameters = new HashMap();
            parameters.put("bps_rept_gn", pi_rept_gn2);

but I don't see where that is put somewhere that would be visible outside of this method.  And this method doesn't call the report, so it can't help you there.  You create the object in the method, then the method ends and the object goes away.

Where do you want the new parameter value to be used to be sent to iReport?
0
 

Author Comment

by:shellybelly999
ID: 34133725
I've linked the scriptlet to the report so that's why I'm not calling the report. There is a parameter defined in the report that's called $P{bps_rept_gn}. I was hoping that the new parameter value would replace the default value of the parameter. But maybe this is not possible. Maybe the parameter value can only be passed at the time that the report is called rather than after the report is already initialized?
0
 
LVL 27

Accepted Solution

by:
mrcoffee365 earned 2000 total points
ID: 34136257
I don't know if you can change a value for the report with the this.setVariableValue call in this scriptlet -- I don't see where the variable is defined, or the report.

But I do know that creating the HashMap will have no effect outside this scriptlet.  So if you need the hashmap, you have to do it differently.
0
Create CentOS 7 Newton Packstack Running Keystone

A bug was filed against RDO for the installation of Keystone v3. This guide is designed to walk you through the configuration for using Keystone v3 with Packstack. You will accomplish this using various repos and the Answers file.

 

Author Comment

by:shellybelly999
ID: 34142050
I'm sorry. I didn't include the .jrxml report file with the code because that's a separate file. The scriptlet was being called from the .jrxml file. After investigating, I found that I need to call the report in a manner similar to this:

jasperReport = JasperCompileManager.compileReport(
          "reports/jasperreports_demo.jrxml");
      jasperPrint = JasperFillManager.fillReport(
          jasperReport, new HashMap(), new JREmptyDataSource());
      JasperExportManager.exportReportToPdfFile(
          jasperPrint, "reports/simple_report.pdf");

So your answer got me on the right track and I'm not trying to pass the parameter from the scriplet called by the report. Now I'm trying to create a little Java app that will call the report and pass the parameter to it. Thanks for your help and please wish me luck!
0
 

Author Closing Comment

by:shellybelly999
ID: 34142059
I didn't supply all the info that Mr. Coffee needed to give a complete solution. But I'm happy because he straightened out my incorrect approach to the problem.
0
 
LVL 27

Expert Comment

by:mrcoffee365
ID: 34142263
Thanks, and good luck!

Also -- it's great that you posted your final solution.  Was it the this.setVariableValue for the named variable that set the value the way you wanted?  As long as you had the call done correctly, as you've posted?
0
 

Author Comment

by:shellybelly999
ID: 34160098
I successfully passed the parameters in my test! In order to pass the parameter, I first created a parameter called $P{ReportTitle} in my iReport.

Then I created a Java program to run the report. Before the statement to fill the report, I created the statements below which change the value in the $P{ReportTitle} parameter to "Successfully Changed Title":

//Preparing parameters
Map parameters = new HashMap();
parameters.put("ReportTitle", "Successfully Changed Title");

Then I filled the report with this code:

JasperFillManager.fillReportToFile(reportDirectory + "\\" + reportName + ".jasper",
               parameters,connection);  // creates .jrprint file

Now back to my project!
0
 
LVL 27

Expert Comment

by:mrcoffee365
ID: 34161107
Great -- thanks for posting!
0

Featured Post

Get 15 Days FREE Full-Featured Trial

Benefit from a mission critical IT monitoring with Monitis Premium or get it FREE for your entry level monitoring needs.
-Over 200,000 users
-More than 300,000 websites monitored
-Used in 197 countries
-Recommended by 98% of users

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Go is an acronym of golang, is a programming language developed Google in 2007. Go is a new language that is mostly in the C family, with significant input from Pascal/Modula/Oberon family. Hence Go arisen as low-level language with fast compilation…
This article is meant to give a basic understanding of how to use R Sweave as a way to merge LaTeX and R code seamlessly into one presentable document.
This video teaches viewers about errors in exception handling.
The viewer will learn how to create and use a small PHP class to apply a watermark to an image. This video shows the viewer the setup for the PHP watermark as well as important coding language. Continue to Part 2 to learn the core code used in creat…
Suggested Courses

771 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question