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Solved

Convert from IList<T> to List<T>

Posted on 2010-11-14
4
681 Views
Last Modified: 2013-12-17
Dear All,


Sometimes this simple conversion works: (in C# )


List<T> result = ilistobject as List<T>;



But sometimes it may give me NULL result and I have to use this:


List<T> result = ilistobject.OfType<T>().ToList<T>();
 

How come?

Thanks a lot!
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Comment
Question by:chenyuhao88
4 Comments
 
LVL 75

Assisted Solution

by:käµfm³d 👽
käµfm³d   👽 earned 150 total points
ID: 34133315
Those are NOT the same operations. In the first, you are attempting to cast an object to a List<T> and if the object is not compatible with a List<T> you are given NULL instead. In the second, you are filtering your list for only objects of type T (OfType<T>) and then returning a list of those objects (ToList).
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LVL 13

Accepted Solution

by:
Naman Goel earned 200 total points
ID: 34134039
System.Collections.Generic.IList<T> is an Interface which is implemented in following System classes
List<T>, SortedList<TKey,TValue>,System.Collections.ObjectModel.Collection<T>, System.Collections.ObjectModel.ReadOnlyCollection<T>

So if we are having a different type of collection object in ilistobject which is not compatible with List<T> then


List<T> result = ilistobject as List<T>;
result will be null.

and  ilistobject.OfType<T>().ToList<T>(); will filter the ilistobject based on type T.

so if we are having an IList<Object>


            IList<object> ilistobject = new object[] { "abcd", 2, 3 };

            List<String> result = ilistobject.OfType<string>().ToList<string>();

we will get abcd in result.

0
 
LVL 35

Assisted Solution

by:Miguel Oz
Miguel Oz earned 150 total points
ID: 34140241
IList<T> supports IEnumerable interface, just pass ilistobject to the list constructor.
IList<string> ilistobject = new string[] { "abcd", "test", "pass" };
List<String> result = new List<string>(ilistobject);

You can add an extra check depending on how your overall code is structured:
            if (ilistobject is IList<string>)
            {
                List<String> result = new List<string>(ilistobject);
            }
       
0
 

Author Closing Comment

by:chenyuhao88
ID: 34161865
Thanks guys!
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