regex expression for up to but not including and split

Posted on 2010-11-16
Last Modified: 2012-05-10
I have a line of text

blah blah blah;blah blah blah

I'm trying to formulate a regex expression to capture everything up to the semicolon.

On a second regex or to replace the earlier, I basically need to split up a string separated by semicolons.

Thanks in advance.
Question by:kblackwel
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LVL 35

Expert Comment

by:Terry Woods
ID: 34150009
$line = preg_replace("/;.*/","",$line);
LVL 35

Expert Comment

by:Terry Woods
ID: 34150028
To split a string separated by semicolons, use:

$my_array = preg_split("/;/",$string);
LVL 35

Expert Comment

by:Terry Woods
ID: 34150035
Ah, I made an assumption you're using PHP - which language are you using?
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Author Comment

ID: 34150163
It's for a ETL, so it has to be regex
LVL 35

Expert Comment

by:Terry Woods
ID: 34150190
Ok, well the patterns I've provided are valid, but the first one requires use of a replace command rather than a capture.

To capture text before the first ; character, use pattern:

LVL 35

Expert Comment

by:Terry Woods
ID: 34150218
Does the string have a fixed (or limited) number of fields? Depending on your regex tool, you might be able to use the following to split a string:


or, with a limited number of fields, something like this:


Author Comment

ID: 34150535
Thank you,

For my needs, all I needed was


That matched blah blah blah up to the semicolon.

The field I'm trying to parse would only have 2 semicolons in it max.

Any thoughts on matching the second blah blah blah past the first semicolon.

Again, thanks on the first solution.

Basically I'm pulling a string out of a DB table. In my etl program, I don't have access to split or anything like that. But regex is available. Trying to use that to parse an address table row that is delimited by semicolons.

Author Comment

ID: 34150542
Actually from the semicolon to end of line would be fine too.
LVL 35

Accepted Solution

Terry Woods earned 125 total points
ID: 34150610
From the first semi-colon to the end of the line:



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