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DOS Command - Parsing File on today's date

I am trying to setup a DOS batch file to be able to run 7-zip on file in a folder.

I need to be able to run this 7-zip on today's date.

Example:

7-zip  filename "today's date"

How do I structure my script to only apply my 7-zip on Today's Date?
0
j4piper
Asked:
j4piper
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1 Solution
 
ThommyCommented:
7-zip  filename %DATE%

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jramsierCommented:
in command prompt you can add this to it: "%date:~10,4%-%date:~4,2%-%date:~7,2%"  it will create "2010-01-29"  Format it as you want.  You can move the 3 sections around to make a different format.
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ThommyCommented:
if you want to build your own date string...

check your date format by typing DATE

if your date format is for example 17/11/2010, you can built your own date string as follows


Set mm=%DATE:~3,2%
Set dd=%DATE:~0,2%
Set yyyy=%DATE:~6,4%

REM Built variable with own date format
set MyDate=%yyyy%-%mm%-%dd%

7-zip  filename %MyDate%

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