<div>
you can set the AlwaysOnTop property of the child window to true. also when doing window.ShowDialog() if you are doing this from the parent window do this instead window.ShowDialog(this)
</div>


you can set the AlwaysOnTop property of the child window to true. also when doing window.ShowDialog() if you are doing this from the parent window do this instead window.ShowDialog(this)

<div>
Hi <br />
<br />
I used Topmost=&quot;True&quot; and that worked a treat. &nbsp;I dont understand the w.dow.showdialog(this) bit though. &nbsp;<br />
<br />
this -- is not recognised. &nbsp;what differance does that make?<br />
<br />
Thanks brasso
</div>


Hi

I used Topmost="True" and that worked a treat.  I dont understand the w.dow.showdialog(this) bit though.  

this -- is not recognised.  what differance does that make?

Thanks brasso

<div>
<div class="content wysiwyg-content">
Hi<br />
<br />
I have an app which has a button that opens a second window and disables the window that opened it. &nbsp;<br />
<br />
This works fine, but if I browse away from the app and then click on it again in the task bar the disabled window appears ontop of the new window.<br />
<br />
How can I get it to display the correct window when the app is clicked in the task bar.<br />
<br />
My code so far is very simple:<br />
<br />
Dim window As New Window2<br />
window.ShowDialog()<br />
<br />
Thanks <br />
Brasso
</div>
</div>


Hi

I have an app which has a button that opens a second window and disables the window that opened it.  

This works fine, but if I browse away from the app and then click on it again in the task bar the disabled window appears ontop of the new window.

How can I get it to display the correct window when the app is clicked in the task bar.

My code so far is very simple:

Dim window As New Window2
window.ShowDialog()

Thanks 
Brasso

WPF App window.ShowDialog()

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